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Vlada [557]
3 years ago
5

True or false

Mathematics
1 answer:
Sindrei [870]3 years ago
6 0
That statement is true, because a differentiable function must be continuous, and the only way to reach two relative maxima,, if the function does not have empty places or jumps, which is what continuity means, is that the graph bends between those two maxima and reach an intermediate minimum.
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Please answer this correctly without making mistakes
Lerok [7]

Answer:

63 gallons

Step-by-step explanation:

3 gallons = 4x 3 = 12 quarts

12+2 = 14

14 x 18 = 252 quarts

252 / 4 = 63 gallons

4 0
3 years ago
choose the equation of a line that is perpendicular to the y axis and passes through the point (5,-2)​
kondaur [170]

Answer:

y = -2

Step-by-step explanation:

The line that is perpendicular to y-axis will be a horizontal line so it's slope is 0 => y = 0x + b or y = b

Using (5,-2) => -2 = b => b = -2

then y = -2

3 0
2 years ago
How much work is done when a crane lifts a 100 N block from 2 m to 6 m above the ground?
Natali5045456 [20]
Im guessing it'll be C, but im not sure so im sorry if this didnt help
6 0
4 years ago
Solve for x : -5|x+1|=10
Sloan [31]

Answer: I got no solution

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Please explain why. Thanks
xxTIMURxx [149]

<h3><u>Question</u> :-</h3>

Is (x-2) is a factor of x³-3x²-x +7 –

  • Yes
  • No ☑

<h3><u>Explanation</u> :-</h3>

We are given –

  • Polynomial function, P(x) = x³-3x²-x +7

  • In order to check if x - 2 is a factor of x³-3x²-x +7 or not, we must show that P(2) = 0.

  • Let's find value of x!

\qquad \twoheadrightarrow\bf P(x) = x³-3x²-x +7

\qquad \twoheadrightarrow\bf Q(x) =x - 2

\qquad \twoheadrightarrow\bf If \:Q(x) = 0

\qquad \twoheadrightarrow\bf x - 2 = 0

\qquad \twoheadrightarrow\bf x = 2

Now Put x = 2 into the polynomial –

\qquad \purple{\twoheadrightarrow\bf P(2) = 2³-3(2)²-2+7}

\qquad \twoheadrightarrow\sf P(2) = 8 - 3 \times 4 +5

\qquad \twoheadrightarrow\sf P(2) = 8 -12 +5

\qquad \twoheadrightarrow\sf P(2) = 13-12

\qquad \purple{\twoheadrightarrow\bf P(2) =1 }

  • Since the value of the polynomial function st x = 2 is not Zero (0). Henceforth, ( x - 2) is a factor of  x³-3x²-x +7.

________________________________________

5 0
2 years ago
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