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3 years ago

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The pressure exerted on an object under water increases by 1 atmosphere every 33 feet below the surface of the water. At sea lev

el, the pressure is l atmosphere. Which equation gives the total pressure p, in atmospheres, exerted on an underwater object at a depth of f feet below sea level? A) P 33 B) p 33f C) p 33f+ 1

1 answer:

olga_2 [115]3 years ago

7 0

Answer:

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A personal computer is bought for $2860. A down payment of $520 is made. The remainder of the cost is paid in 20 equal payments.

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C.None of these

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The graph of which function has a minimum located at (4, –3)?

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Answer:

None of the options is the answer to the question

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

$f(x)=a(x-h)^{2}+k$

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$f(x)=x^{2}+4x-11$

In this case the x-coordinate of the vertex will be negative

therefore

case A is not the solution

case B) we have

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The vertex is the point $(4,-3)$ <u>but is not a minimum</u>

see the attached figure

therefore

case B is not the solution

case C) we have

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Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)-5=x^{2}-4x$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)-5+4=(x^{2}-4x+4)$

$f(x)-1=(x^{2}-4x+4)$

Rewrite as perfect squares

$f(x)-1=(x-2)^{2}$

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case C is not the solution

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$f(x)-35=2x^{2}-16x$

Factor the leading coefficient

$f(x)-35=2(x^{2}-8x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)-35+32=2(x^{2}-8x+16)$

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$f(x)-3=2(x-4)^{2}$

$f(x)=2(x-4)^{2}+3$ --------> vertex form

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therefore

case D is not the solution

The answer to the question will be the function

$f(x)=2x^{2}-16x+29$

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