For this case we have the following table:
x f(x)
<span><span><span>0 2
</span><span>1 5
</span><span>2 10
</span><span>3 17
</span></span></span> The equation that best fits the data in the table, for this case, is given by a quadratic function.
<span><span><span> </span></span></span>The quadratic function in its standard form is:
f (x) = x2 + 2x + 2
Answer:
f (x) = x2 + 2x + 2
Answer:
Step-by-step explanation:
A. x = -2 and y = -5
check:
x^2 - 9 = 0
B. x = 0 and y = -6
check:
x^2 - 6 = 0
C. x1 = 3, x2 = 5
check:
(x - 3)(x - 5) = 0
D. x1 = 0, x2 = 4
check:
x(x - 4) = 0
Answer:
the answer is B
Step-by-step explanation:
