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ahrayia [7]
3 years ago
8

108 rounded to the nearest tenth

Mathematics
2 answers:
Artemon [7]3 years ago
8 0

Answer:

110

Step-by-step explanation:

Vikentia [17]3 years ago
5 0
110 is right I believe
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Answer:

8.34/1

Step-by-step explanation:

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College LEVEL can you help me? :S
Yanka [14]

Although the formula looks involved, the key here is looking to see where the information goes.

We are given all the pieces but need to convert mph to ft/s to use the formula. Let's do it with 1 mph so that we have a ratio to use. We and solve a unit conversion problem.

\frac{1mile}{hour} * \frac{hour}{60 minutes} * \frac{minute}{60 seconds} * \frac{5280 feet}{mile} = \frac{5280}{60*60} = \frac{5280}{3600} = 1.46666

That ratio tells us that 1 mph is 1.466666 ft/s. Now we solve two proportions.

1 mph / 1.466666 feet per second = 60 mph / x feet per second.

1x = (60)(1.466666)

So x = 88 feet per second.


Next, We repeat for 24 mph.

1 mph / 1.46666 feet per second = 24 mph / x feet per second.

1x = (1.4666666)(24)

x = 35.2 feet per second


Now we have the found appropriate V₁ and V₂. V₁ > V₂, so V₁ is 88 ft/s and V₂ is 35.2 ft/s. The problem tells us θ = 2.3 degrees, K₁ = .4 and K₂ = .06. The rest of the problem is calculator work. Start by substituting our degree measure of 2.3 degrees and the given values in the problem for V₁, V₂, K₁, and K₂

D = \frac{1.05[(88)^{2}-(35.2)^{2}]}{64.4(.4+.06 + (sin 2.3))}

D = \frac{1.05[(7744-1239.04]}{64.4(.46 + (sin 2.3))}

D = \frac{1.05(6504.96)}{64.4(.46 + 0.04013)}

D = \frac{6830.208}{64.4(0.50013)}

D = 6830.208 / 32.208372

D = 212.0631 = 212 (to the nearest foot)


Thus the car needs 212 feet to stop.

6 0
3 years ago
According to the article "Fatigue Testing of Condoms" (Polymer Testing, 2009: 567–571), "tests currently used for condoms are su
daser333 [38]

Answer:

99% Confidence interval:  (1196,1973)

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 20

Mean, μ = 1584

Standard Deviation, σ = 607

99% Confidence interval:  

\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}  

Putting the values, we get,  

t_{critical}\text{ at degree of freedom 19 and}~\alpha_{0.01} = \pm 2.86  

1584 \pm 2.86(\dfrac{607}{\sqrt{20}} )\\\\ = 1584 \pm 388.18\\ = (1195.82 ,1972.18)\\ \approx (1196,1973)

Thus, there is a 99% chance that it will break in approximately 1196 to 1972

6 0
3 years ago
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