-5h-3(10+h) = -6
-5h-30-3h = -6
Add/subtract like terms
-8h -30 = -6
Add 30 to both sides
-8h = 24
Divide by -8 to isolate h
h = -3
The solution to the expression using the FOIL method is x⁴ - 6x² + 8
<h3>How to evaluate the expression using FOIL?</h3>
From the question, we have the following parameters that can be used in our computation:
(X2-2)(x2-4)
Rewrite the expression properly
So, we have
(x² -2)(x² - 4)
The FOIL method states that: First, Outside, Inside, and Last
Using the acronym as a guide, we have
(x² -2)(x² - 4)
Expand the expression
This gives
(x² -2)(x² - 4) = x²(x² - 4) -2(x² - 4)
Expand the brackets
So, we have the following representation
(x² -2)(x² - 4) = x⁴ - 4x² -2x² + 8
Collect the like terms
This gives
(x² -2)(x² - 4) = x⁴ - 4x² -2x² + 8
Lastly, we evaluate the like terms
(x² -2)(x² - 4) = x⁴ - 6x² + 8
Hence, the solution to the equation is x⁴ - 6x² + 8
Read more about expressions at
brainly.com/question/4344214
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Answer:
The volume of cone A is twice the volume of cone B.
Step-by-step explanation:
The formula that is used to find the volume of a cone is given by :
![V=\dfrac{1}{3}\pi r^2 h](https://tex.z-dn.net/?f=V%3D%5Cdfrac%7B1%7D%7B3%7D%5Cpi%20r%5E2%20h)
Where
r is radius of cone and h is height
ATQ,
The radius of the base of cone A is twice as large as the radius of the base of cone B. The height of cone B is twice the height of cone A.
![r_A=2r_B\ \text{and}\ h_B=2h_A](https://tex.z-dn.net/?f=r_A%3D2r_B%5C%20%5Ctext%7Band%7D%5C%20h_B%3D2h_A)
or
![\dfrac{r_A}{r_B}={2}\ \text{and}\ \dfrac{h_A}{h_B}=\dfrac{1}{2}](https://tex.z-dn.net/?f=%5Cdfrac%7Br_A%7D%7Br_B%7D%3D%7B2%7D%5C%20%5Ctext%7Band%7D%5C%20%5Cdfrac%7Bh_A%7D%7Bh_B%7D%3D%5Cdfrac%7B1%7D%7B2%7D)
Taking ratios of their volume,
![\dfrac{V_A}{V_B}=\dfrac{1/3\pi r_A^2h_A}{1/3\pi r_B^2h_B}\\\\\dfrac{V_A}{V_B}=(\dfrac{r_A}{r_B})^2\times \dfrac{h_A}{h_B}](https://tex.z-dn.net/?f=%5Cdfrac%7BV_A%7D%7BV_B%7D%3D%5Cdfrac%7B1%2F3%5Cpi%20r_A%5E2h_A%7D%7B1%2F3%5Cpi%20r_B%5E2h_B%7D%5C%5C%5C%5C%5Cdfrac%7BV_A%7D%7BV_B%7D%3D%28%5Cdfrac%7Br_A%7D%7Br_B%7D%29%5E2%5Ctimes%20%5Cdfrac%7Bh_A%7D%7Bh_B%7D)
So,
![\dfrac{V_A}{V_B}=(\dfrac{r_A}{r_B})^2\times \dfrac{h_A}{h_B}\\\\\dfrac{V_A}{V_B}=(2)^2\times \dfrac{1}{2}\\\\\dfrac{V_A}{V_B}=2\\\\V_A=2V_B](https://tex.z-dn.net/?f=%5Cdfrac%7BV_A%7D%7BV_B%7D%3D%28%5Cdfrac%7Br_A%7D%7Br_B%7D%29%5E2%5Ctimes%20%5Cdfrac%7Bh_A%7D%7Bh_B%7D%5C%5C%5C%5C%5Cdfrac%7BV_A%7D%7BV_B%7D%3D%282%29%5E2%5Ctimes%20%5Cdfrac%7B1%7D%7B2%7D%5C%5C%5C%5C%5Cdfrac%7BV_A%7D%7BV_B%7D%3D2%5C%5C%5C%5CV_A%3D2V_B)
The volume of cone A is twice the volume of cone B.
Answer:
X= 8
Y= 130
(8, 130)
Step-by-step explanation:
I used a graphing calculator to see where the two equations intersected.
Hope this helped :)