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k0ka [10]
3 years ago
15

Indicate the equation of the line, in standard form, that is the perpendicular bisector of the segment with endpoints (4, 1) and

(2, -5).
Mathematics
1 answer:
Anika [276]3 years ago
3 0

9514 1404 393

Answer:

  x +3y = -3

Step-by-step explanation:

The midpoint of the segment with the given end points is ...

  M = ((4, 1) +(2, -5))/2 = (6, -4)/2 = (3, -2)

The difference between coordinates of the given points is ...

  (∆x, ∆y) = (4, 1) -(2, -5) = (2, 6)

__

The equation of the perpendicular bisector can be written as ...

  ∆x(x -h) +∆y(y -k) = 0 . . . . line through (h, k) ⊥ to one with slope ∆y/∆x

  2(x -3) +6(y -(-2)) = 0

  2x +6y +6 = 0 . . . . . simplify to a general-form equation

To put this in standard form, we need the constant on the right, and all numbers mutually prime. We can subtract 6 and divide by 2 to get there.

  2x +6y = -6

  x + 3y = -3

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When the sum of \, 528 \, and three times a positive number is subtracted from the square of the number, the result is \, 120. F
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Let x be the unknown number. So, three times that number means 3x, and the square of the number is x^2

We have to sum 528 and three times the number, so we have 528+3x

Then, we have to subtract this number from x^2, so we have

x^2-(3x+528)

The result is 120, so the equation is

x^2 - 3x - 528 = 120 \iff x^2 - 3x - 648 = 0

This is a quadratic equation, i.e. an equation like ax^2+bx+c=0. These equation can be solved - assuming they have a solution - with the following formula

x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

If you plug the values from your equation, you have

x_{1,2} = \dfrac{3\pm\sqrt{9-4\cdot(-648)}}{2} = \dfrac{3\pm\sqrt{9+2592}}{2} = \dfrac{3\pm\sqrt{2601}}{2} = \dfrac{3\pm51}{2}

So, the two solutions would be

x = \dfrac{3+51}{2} = \dfrac{54}{2} = 27

x = \dfrac{3-51}{2} = \dfrac{-48}{2} = -24

But we know that x is positive, so we only accept the solution x = 27

6 0
3 years ago
Which expression can be used to solve 3/5 divide by 7/10
kramer

Answer:

\frac{3}{5} *\frac{10}{7}  

=  \frac{30}{35} =\frac{6}{7}

7 0
3 years ago
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