Answer:
B: 1/3
Step-by-step explanation:
The original shape is getting bigger so it must be a whole number greater than 1. And the shape is still there so it can't be 0. The only other answer is 3.
Answer:
i. The area of the entire circle is approximately 113 squared units.
ii. Area of the sector ACB is approximately 28 squared units.
iii. Area of the shaded region is approximately 14 squared units.
Step-by-step explanation:
a. Area of a circle =
where r is the radius
The area of the entire circle =
= ×
= × 36
= 36 squared units
= 113.143 squared units
The area of the entire circle is approximately 113 squared units.
b. Area of the sector ACB = (θ ÷ 2) ×
= (θ ÷ 2) × 36
But, θ = rad. So that:
Area of the sector ACB = ( ÷ 2) × 36
= 9 squared units
= 28.286 squared units
Area of the sector ACB is approximately 28 squared units.
c. Area of the shaded region = Area of triangle CDE
Area of triangle = × base × height
Draw a perpendicular bisector of DE from C, then apply Pythagoras theorem so that:
h =
=
= 5.453 units
Thus,
Area of the shaded region = × 5 × 5.453
= 13.633 squared units
Area of the shaded region is approximately 14 squared units.
Total 52 students.
52 - 17 = 35 students left
35 - 5 = 30 students left
30 - 2 = 28 students left
Each class has 11 students that play ONE sport, which means 22 total in 2 classes. You're on your own now! It's not that hard, I'm sure you'll figure it out.
You basically plot the 2 on the Y side and then count up once and 3 times to the right since it’s a positive, and then you’ll plot the -3 on the negative side and count up twice and move it once to the right since it’s also a positive. Hope i helped and explained myself in and understanding way :)
D is the answer because if you calculate the answer correctly. that will be so.