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Vitek1552 [10]
3 years ago
6

Express the trigonometric ratios sinA in term of cosA​

Mathematics
1 answer:
MariettaO [177]3 years ago
8 0

Answer:

sinA = ± \sqrt{1-cos^2A}

Step-by-step explanation:

Using the Pythagorean identity

sin²A + cos²A = 1 ( subtract cos²A from both sides )

sin²A = 1 - cos²A ( take the square root of both sides )

sinA = ± \sqrt{1-cos^2A}

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No Solution.

Step-by-step explanation:

2 - 3(x + 4) = 3(3 - x)

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I NEED HELP ON NUMBER 8 PLSSSS
antiseptic1488 [7]

Answer:

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Step-by-step explanation:

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Read 2 more answers
DG , EG , and FG are perpendicular bisectors of the sides of △ABC . DG= 5 cm and BD= 12 cm.
weqwewe [10]
The answer is that CG is equal to 13cm.
As given that DG, EG, and FG are perpendicular bisectors of the sides of triangle ABC and it shows that G is the point of intersection and also it is the circumcenter of the triangle, So;
AG = BG = CG
By Pythagorean theorem
BG² = DG² + BD²BG²
And DG = 5cm and BD = 12cm
So,
BG = √(DG² + BD²) = √(5² + 12²) = √(25 + 144) = √169 = 13
BG = 13 = AG = CG
Thus,
 CG = 13cm
6 0
3 years ago
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