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Vitek1552 [10]
3 years ago
6

Express the trigonometric ratios sinA in term of cosA​

Mathematics
1 answer:
MariettaO [177]3 years ago
8 0

Answer:

sinA = ± \sqrt{1-cos^2A}

Step-by-step explanation:

Using the Pythagorean identity

sin²A + cos²A = 1 ( subtract cos²A from both sides )

sin²A = 1 - cos²A ( take the square root of both sides )

sinA = ± \sqrt{1-cos^2A}

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