A forklift raises a 1,020 N crate 3.50 m up to a shelf. How much work is done by the forklift on the crate

At a NASCAR racetrack, the distance per lap is 2 miles. Lou Lambert drives his car at a constant rate of 160 miles per hour. Ral

Nezavi [6.7K]

Answer:

24 minutes

Step-by-step explanation:

Given:

Distance per lap = 2 miles

Speed of Lou Lambert = 160 miles/hr

Speed of Ralph Redding = 170 miles/hr

Speed difference between the two = 170 - 160 = 10 miles/hr

Therefore, we can say that Ralph gains 10 miles in 60 minutes over Lou.

We have to find the time in which Ralph will gain 2 laps i.e. 2 $\times$ 2 = 4 miles.

Let us use unitary method to find the required time.

10 miles are gained by Ralph in 60 minutes

1 mile will be gained in $\frac{60}{10} = 6\ minutes$

4 miles will be gained in 6 $\times$ 4 = 24 minutes

7 0

3 years ago

Determine whether or not the given value is a solution for the equation. Answer Yes or No

igor_vitrenko [27]

Y=24 is a solution for the equation.

y/12=2 is solved by multiplying both sides by 12 to get y by itself. so you'd end up multiplying 2 • 12 which equals 24.

5 0

3 years ago

In this problem we consider an equation in differential form Mdx+Ndy=0. (4x+2y)dx+(2x+8y)dy=0 Find My= 2 Nx= 2 If the problem is

zheka24 [161]

Answer:

$f(x,y)=2x^2+4y^2+2xy=C_1\\\\Where\\\\y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )$

Step-by-step explanation:

Let:

$M(x,y)=4x+2y\\\\and\\\\N(x,y)=2x+8y$

This is and exact equation, because:

$\frac{\partial M(x,y)}{\partial y} =2=\frac{\partial N}{\partial x}$

So, define f(x,y) such that:

$\frac{\partial f(x,y)}{\partial x} =M(x,y)\\\\and\\\\\frac{\partial f(x,y)}{\partial y} =N(x,y)$

The solution will be given by:

$f(x,y)=C_1$

Where C1 is an arbitrary constant

Integrate $\frac{\partial f(x,y)}{\partial x}$ with respect to x in order to find f(x,y):

$f(x,y)=\int\ {4x+2y} \, dx =2x^2+2xy+g(y)$

Where g(y) is an arbitrary function of y.

Differentiate f(x,y) with respect to y in order to find g(y):

$\frac{\partial f(x,y)}{\partial y} =2x+\frac{d g(y)}{dy}$

Substitute into $\frac{\partial f(x,y)}{\partial y} =N(x,y)$

$2x+\frac{dg(y)}{dy} =2x+8y\\\\Solve\hspace{3}for\hspace{3}\frac{dg(y)}{dy}\\\\\frac{dg(y)}{dy}=8y$

Integrate $\frac{dg(y)}{dy}$ with respect to y:

$g(y)=\int\ {8y} \, dy =4y^2$

Substitute g(y) into f(x,y):

$f(x,y)=2x^2+4y^2+2xy$

The solution is f(x,y)=C1

$f(x,y)=2x^2+4y^2+2xy=C_1$

Solving y using quadratic formula:

$y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )$

4 0

4 years ago

The pic is here , just the question wouldn’t show up right. Any help ?

coldgirl [10]

Answer:

its 4√2i i think

Step-by-step explanation:

3 0

4 years ago

Read 2 more answers

Is −4[3(x−7)] and 6(14−2x) equiviant

Paraphin [41]

Answer:

Yes.

Step-by-step explanation:

Set the equations equal to each other to determine their equality.

-4[3(x - 7)] = 6(14 - 2x)

Distribute the 3 and the 6 into their respective parenthesis.

-4[3x - 21] = 84 - 12x

Distribute the -4 into the brackets.

-12x + 84

Rearrange the equations.

84 - 12x = 84 - 12x

Since the equations come out to be the same thing on both sides so that any value satisfies it, the equations are equivalent.

4 0

3 years ago