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Alenkasestr [34]
3 years ago
8

Deshawn fuels 2 yachts and 6 barges.

Mathematics
1 answer:
Dovator [93]3 years ago
4 0

The number of boats are 8; so, he needs a total of 8*126 gallons.

In order to get the partial products, first you have to decompose 126 in its hundreds, tens and ones, that is, 126 = 100 + 20 + 6. Then multiply each of this terms by 8, as follows

8*100 = 800

8*20 = 160

8*6 = 48

Finally you have to add the results of these multiplications, that is, 800 + 160 + 48 = 1008. Therefore, he needs 1008 gallons for all the boats.

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