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nata0808 [166]
3 years ago
15

I need help with this question

Mathematics
1 answer:
Anika [276]3 years ago
3 0
1/4 because you have to simplify your answer.
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6 6/15 because if you multiply the mixed number first then multiply the fraction
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Express (25 1/2) ^3 in simplest radical form
Mkey [24]

Step-by-step explanation:

i think this is the answer if it's wrong I'm sorry

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3 years ago
Consider the following function. f(x) = 16 − x2/3 Find f(−64) and f(64). f(−64) = f(64) = Find all values c in (−64, 64) such th
VARVARA [1.3K]

Answer:

This does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64).

Step-by-step explanation:

The given function is

f(x)=16-\frac{x^2}{3}

To find f(-64), we substitute x=-64 into the function.

f(-64)=16-\frac{(-64)^2}{3}

f(-64)=16-\frac{4096}{3}

f(-64)=-\frac{4048}{3}

To find f(64), we substitute x=64 into the function.

f(64)=16-\frac{(64)^2}{3}

f(64)=16-\frac{4096}{3}

f(64)=-\frac{4048}{3}

To find f'(c), we must first find f'(x).

f'(x)=-\frac{2x}{3}

This implies that;

f'(c)=-\frac{2c}{3}

f'(c)=0

\Rightarrow -\frac{2c}{3}=0

\Rightarrow -\frac{2c}{3}\times -\frac{3}{2}=0\times -\frac{3}{2}

c=0

For this function to satisfy the Rolle's Theorem;

It must be continuous on [-64,64].

It must be differentiable  on (-64,64).

and

f(-64)=f(64).

All the hypotheses are met, hence this does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64) is the correct choice.

6 0
3 years ago
Read 2 more answers
-3j - (-4) over -6 = 12 j= ? ​
babymother [125]

Answer:

j =76/3

Step-by-step explanation:

-3j -  -4

------------------ = 12

-6

Multiply each side by -6 to clear the fraction

-3j +4

------------------ * -6 = 12 *-6

-6

-3j +4 = -72

Subtract 4 from each side

-3j +4-4 = -72 -4

-3j = -76

Divide each side by -3

-3j/-3 = -76/-3

j = 76/3

5 0
4 years ago
Is 11/20 repeating or terminating
Dmitrij [34]
It is terminating it is 45/100
7 0
3 years ago
Read 2 more answers
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