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never [62]
3 years ago
13

Select either relation (if the set is a relation but not a function), function (if the set is both a relation and a function), o

r neither (if the set is not a relation). A = {(1, 2) (2, 2) (3, 2) (4, 2)}
relation
function
neither
Mathematics
2 answers:
gavmur [86]3 years ago
5 0

Answer:

B. Function.

Step-by-step explanation:

We have been given a set. We are asked to choose the correct option about the given set.

We know that a set represents a relation, when each x value corresponds to a y-value. In a relation one x-coordinate can have more than one y-values.

We know that a set represents a function, where each x-value corresponds to exactly one y-value.

Two different value can have same y-value to be a function.

We can see that each value of x corresponds to exactly one y-value. The value of y is 2 for all value of x, therefore, all points lie on a horizontal line y=2.

Therefore, our given set a function.

kirill [66]3 years ago
3 0

Answer:

B. Function.

Step-by-step explanation:

We have been given a set. We are asked to choose the correct option about the given set.

You might be interested in
The slope of EF¯¯¯¯¯ is −52.
9966 [12]

Based on the above, the segments that are perpendicular to EF are LM and NP.

<h3>Why is the segment are LM and NP perpendicular  to EF ?</h3>

Note that when two lines are perpendicular, we can say that;

M1 * M2 = -1 As M1 and M2 are known to be the slopes of the lines.

Therefore, when the the slope of EF is said to be −5/2, then  one can say that the slope of  the segment that is said to be  perpendicular to EF will have to be equal to m1*m2=-1, m2=-1/m1, m2=-1/(-5/2) or m2=2/5.

Scenario one:

JK , if J is at (3, −2) and K is at (5, −7)

To find the slope JK, then

m=(y2-y1)/x2-x1)

m=(-7+2)/(5-3)

m=-5/2

-5/2 is not equal to 2/5

Therefore,  JK is not perpendicular to EF

Scenario 2

Find GH , when G is at (6, 7) and H is at (4, 12)

To find the slope GH

m=(y2-y1)/x2-x1)

m=(12-7)/(4-6)

m=5/-2

m=-5/2

Since -5/2 is not equal to 2/5 then GH is not perpendicular to EF

Scenario 3:

Find LM , If L is at (1, 9) and M is at (6, 11)

To find the slope LM, then

m=(y2-y1)/x2-x1)

m=(11-9)/(6-1)

m=2/5

Since 2/5 is equal to 2/5

Then LM is perpendicular to EF

Scenario 4:

Find NP , if N is at (−3, 4) and P is at (−8, 2)

To find the slope NP, then

m=(y2-y1)/x2-x1)

m=(2-4)/(-8+3)

m=-2/-5

m=2/5

Since 2/5 is equal to 2/5.

Therefore,  NP is perpendicular to EF

Based on the above calculations, the segments that are perpendicular to EF are LM and NP.

See correct format of question written below

The slope of EF is −5/2 .

Which segments are perpendicular to EF?

Select all the right answers please

1. JK , where J is at (3, −2) and K is at (5, −7)

2. GH , where G is at (6, 7) and H is at (4, 12)

3. LM , where L is at (1, 9) and M is at (6, 11)

4. NP , where N is at (−3, 4) and P is at (−8, 2)

Learn more about segments from

brainly.com/question/10565562

#SPJ1

5 0
2 years ago
Question 1:
Morgarella [4.7K]

Answer:

Step-by-step explanation:

KE = ½mv²

KE₁₀ = ½(1100)10² = 55000 = 55 kJ

KE₃₀ = ½(1100)30² = 495000 = 495 kJ

9 times greater

3 0
2 years ago
Put -9.3 and -4.125 and -2.25 in order from least to greatest
DedPeter [7]
It would be : -9.3 , -4.125 and -2.25.

Hope This Helps You!
Good Luck Studying :)
7 0
3 years ago
Read 2 more answers
two submarines, one red and one blue, started rising toward the surface at the same time.they each rose at a constant speed. the
Mnenie [13.5K]

I NEED A BIT MORE DETAIL LOL

6 0
3 years ago
What is the answer for x ?
Bingel [31]
I think its probaly going to be 6
5 0
2 years ago
Read 2 more answers
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