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pashok25 [27]
3 years ago
11

Shania has $45in her wallet. She spends $4 on snacks $8 on a movie ticket.What integer represents the change in amount of money

in her wallet?How money does she hAve left.
Mathematics
1 answer:
jeyben [28]3 years ago
5 0
She has $32 left in her pocket
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Find the Area of the figure below, composed of a rectangle and a semicircle. The radius of the circle is shown. Round to the nea
liraira [26]

Answer: My friend told me it is 79

8 0
2 years ago
Prove that it is impossible to dissect a cube into finitely many cubes, no two of which are the same size.
solniwko [45]

explanation:

The sides of a cube are squares, and they are covered by the respective sides of the cubes covering that side of the big cube. If we can show that a sqaure cannot be descomposed in squares of different sides, then we are done.

We cover the bottom side of that square with the bottom side of smaller squares. Above each square there is at least one square. Those squares have different heights, and they can have more or less (but not equal) height than the square they have below.

There is one square, lets call it A, that has minimum height among the squares that cover the bottom line, a bigger sqaure cannot fit above A because it would overlap with A's neighbours, so the selected square, lets call it B, should have less height than A itself.

There should be a 'hole' between B and at least one of A's neighbours, this hole is a rectangle with height equal to B's height. Since we cant use squares of similar sizes, we need at least 2 squares covering the 'hole', or a big sqaure that will form another hole above B, making this problem inifnite. If we use 2 or more squares, those sqaures height's combined should be at least equal than the height of B. Lets call C the small square that is next to B and above A in the 'hole'. C has even less height than B (otherwise, C would form the 'hole' above B as we described before). There are 2 possibilities:

  • C has similar size than the difference between A and B
  • C has smaller size than the difference between A and B

If the second case would be true, next to C and above A there should be another 'hole', making this problem infinite. Assuming the first case is true, then C would fit perfectly above A and between B and A's neighborhood.  Leaving a small rectangle above it that was part of the original hole.

That small rectangle has base length similar than the sides of C, so it cant be covered by a single square. The small sqaure you would use to cover that rectangle that is above to C and next to B, lets call it D, would leave another 'hole' above C and between D and A's neighborhood.

As you can see, this problem recursively forces you to use smaller and smaller squares, to a never end. You cant cover a sqaure with a finite number of squares and, as a result, you cant cover a cube with finite cubes.

3 0
3 years ago
The ratio of rabbits to cats is 2:4 respectively. If there are
Natasha_Volkova [10]

Answer:

there are 36 cats in one house the ratio is 1:2

Step-by-step explanation:

3 0
3 years ago
2 3/8 • 1 1/6 <br> Help step sis I'm stuck
svlad2 [7]

Answer:

2.77083333333

Step-by-step explanation:

I assume. Do not hold me account for mistakes, I apologize if my work is incorrect. Have a good day/night :}

6 0
2 years ago
Read 2 more answers
A line segment whose endpoints are (2,6) and (8,y) is perpendicular to a line whose slope is -4. What is the value of y?
Mariulka [41]
If the line segment is perpendicular to a line with the slope of -4, that means the line segment has a slope of 1/4.

First let's make an equation for the line segment using the slope of 1/4 and the point at (2,6) to find the final piece, the y-intercept

y = mx + b
6 = 1/4(2) + b
6 = 2/4 + b
24/4 = 2/4 + b
22/4 = b

y = 1/4 x + 22/4
6 = 1/4(2) + 22/4
6 = 2/4 + 22/4
6 = 24/4
6 = 6 <-- proves that this equation is correct

Now you may plug in the x to find y. ( 8 , y )
y = 1/4(8) + 22/4
y = 8/4 + 22/4
y = 30/4 = 15/2 = 7.5
4 0
3 years ago
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