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4 years ago

How to find area of a shape

1 answer:

7 0

Answer: you would tend to take the main dimensions of the shape like height times width and add what you need for the shape that you are finding the area for ; circles= pie2r trinagle=h*w/2 squre=s2 rectangle w*h

Step-by-step explanation:

You might be interested in

Two variables are correlated with r = 0.44.

butalik [34]

It's moderate positive because when the number is closer to zero the weaker it is and the closer to one its stronger so since 0.44 is in more in the middle it moderate and since there is no negative sign which is - then it moderate positive. Btw I took the test and it was right.

3 0

3 years ago

F(x+k) what is the value of k

guapka [62]

Answer:

k = -3

Hope this helps!

6 0

3 years ago

Read 2 more answers

When we test Upper H 0: muequals0 against Upper H Subscript a: mugreater than0, we get a P-value of 0.03. a. What would the

Anastasy [175]

Answer:

(a) The null hypothesis will be rejected.

(b) Type I error

Step-by-step explanation:

The hypothesis provided is:

$H_{0}: \mu = 0\\ H_{a} : \mu > 0$

The p-value of the test obtained is 0.03

(a)

Decision rule for hypothesis testing, based on p-value, states that if the p-value is less than the significance level (α) then the null hypothesis is rejected and vice versa.

The significance level is α = 0.10

Then,

$p-value = 0.03 < \alpha = 0.10$

Thus, the null hypothesis will be rejected.

Conclusion:

The null hypothesis is rejected stating that the value of μ is more than 0.

(b)

If the decision in (a) is an error, i.e. the null hypothesis is rejected when in fact it is true, this type of error is known as type I error.

(c)

The significance level is α = 0.01

Then,

$p-value = 0.03 > \alpha = 0.01$

Thus, the null hypothesis will not be rejected.

Conclusion:

The null hypothesis was not rejected stating that the value of μ is 0.

If this decision is an error, i.e. the null hypothesis was not rejected when in fact it is false, this type of error is known as type II error.

3 0

3 years ago

If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalen

Alisiya [41]

The answer is <span>2(–4y + 13) – 3y = –29

Step 1: Express </span><span>x from the second equation
Step 2: Substitute x into the first equation:

The system of equations is:
</span><span>2x – 3y = –29
x + 4y = 13

Step 1:
</span>The second equation is: x + 4y = 13
Rearrange it to get x: x = - 4y + 13

Step 2:
The first equation is: 2x – 3y = –29
The second equation is: x = - 4y + 13
Substitute x from the second equation into the first one:
2(-4y + 13) - 3y = -29

Therefore, the second choice is correct.

5 0

4 years ago

Rewrite using the distributive property and GCF 16 + 40

Artist 52 [7]

The GCF of 16 and 40 is 8.

16/8 = 2

40/8 = 5

We can rewrite this using the distribute property like so:

Using the distributive property:

16 + 40

16 + 40 = 56

We can also add inside the parentheses and multiply and we'll get the same answer.

8(7)

8 0

4 years ago