The answer is (A) 2, hope this helps!
Let AB extended intersect DC extended at point E
<span>We now have right triangle BEC with E = 90 degrees </span>
<span>For triangle BEC: </span>
<span>Exterior angle at E = 90 </span>
<span>Exterior angle at C = 148 (given) </span>
<span>Exterior angle of all polygons add up to 360 degrees </span>
<span>Exterior angle at B = 360−148−90 = 122 </span>
<span>So in quadrilateral ABCD </span>
<span>B = 122 </span>
<span>D = 360−44−148−122 = 46</span>
It will be 21/40
probability getting both white marbles
3/8×4/10=12/80
probability getting both black marbles
5/8×6/10=30/80
12/80+30/80=42/80= 21/80
Answer:
Step-by-step explanation:
Hey there!!!
According to the question,
Angle P is three less than twice less of an angle Q.
Then, let angle Q be x then angle P is 2x-3.
Now, it has also given that they are supplementary angle.
We know that the sum of supplementary angle is 180°.
Therefore, x+ 2x - 3°=180°.
Or, 3x = 180°-3°
Or, x = 177°/3
Therefore the measure of angle Q is 59° and P is 2×59°-3°= 121°.
Hope it helps....
There are 3 because 12 divided by 4 is 3.