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I dont know. Help?<br> Please and Thanks

a_sh-v [17]

Answer:

Y' (5, -3), Z' (3, -2)

Step-by-step explanation:

The translation is right 4 and down 1. Since you are going from (3, -4) to (7, -5), to get from 3 to 7 on the x axis you move right 4. To get from -4 to -5 on the y axis, you go down 1.

Y (1, -2) add 4 to the x value. 1 + 4 = 5. Add -1 to the y value. -2 + -1 = -3. Y' (5, -3)

Z (-1, -1). Add 4 to the x value. 4 + (-1) = 3. Add -1 to the y value. -1 + (-1) = -2.

4 0

3 years ago

A builder was building a fence. In the moring he worked 2/5 of an hour. In the afternoon he wirked for 9/10 of an hour how many

Burka [1]

Answer:

2 1/4 times

Step-by-step explanation:

A builder was building a fence. In the moring he worked 2/5 of an hour. In the afternoon he wirked for 9/10 of an hour. how many times as long in the morning did he work in the afternoon

Note that:

1 hour = 60 minutes

In the moring he worked 2/5 of an hour.

= 2/5 × 60 minutes

= 24 minutes

In the afternoon he worked for 9/10 of an hour

Hence:

9/10 × 60 minutes

= 54 minutes

How many times as long in the morning did he work in the afternoon?

This is calculated as number of minutes worked in the afternoon ÷ Number of minutes worked in the morning

= 54 minutes/24 minutes

= 2 6/24

= 2 1/4 times

4 0

3 years ago

Suppose that 50% of all young adults prefer McDonald's to Burger King when asked to state a preference. A group of 12 young adul

ddd [48]

Answer:

a) 0.194 = 19.4% probability that more than 7 preferred McDonald's

b) 0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred McDonald's

c) 0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred Burger King

Step-by-step explanation:

For each young adult, there are only two possible outcomes. Either they prefer McDonalds, or they prefer burger king. The probability of an adult prefering McDonalds is independent from other adults. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

50% of all young adults prefer McDonald's to Burger King when asked to state a preference.

This means that $p = 0.5$

12 young adults were randomly selected

This means that $n = 12$

(a) What is the probability that more than 7 preferred McDonald's?

$P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{12,8}.(0.5)^{8}.(0.5)^{4} = 0.121$

$P(X = 9) = C_{12,9}.(0.5)^{9}.(0.5)^{3} = 0.054$

$P(X = 10) = C_{12,10}.(0.5)^{10}.(0.5)^{2} = 0.016$

$P(X = 11) = C_{12,11}.(0.5)^{11}.(0.5)^{1} = 0.003$

$P(X = 12) = C_{12,12}.(0.5)^{12}.(0.5)^{0} = 0.000$

$P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) = 0.121 + 0.054 + 0.016 + 0.003 + 0.000 = 0.194$

0.194 = 19.4% probability that more than 7 preferred McDonald's

(b) What is the probability that between 3 and 7 (inclusive) preferred McDonald's?

$P(3 \leq X \leq 7) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{12,3}.(0.5)^{3}.(0.5)^{9} = 0.054$

$P(X = 4) = C_{12,4}.(0.5)^{4}.(0.5)^{8} = 0.121$

$P(X = 5) = C_{12,5}.(0.5)^{5}.(0.5)^{7} = 0.193$

$P(X = 6) = C_{12,6}.(0.5)^{6}.(0.5)^{6} = 0.226$

$P(X = 7) = C_{12,7}.(0.5)^{7}.(0.5)^{5} = 0.193$

$P(3 \leq X \leq 7) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) = 0.054 + 0.121 + 0.193 + 0.226 + 0.193 = 0.787$

0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred McDonald's

(c) What is the probability that between 3 and 7 (inclusive) preferred Burger King?

Since $p = 1-p = 0.5$ , this is the same as b) above.

So

0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred Burger King

7 0

3 years ago

Rewrite the equation by completing the square. 4 x^2 +20 x +25 = 0

Sav [38]

Answer:

x=-5/2

Step-by-step explanation:

4 x^2 +20 x +25 = 0

x^2+5x=-25/4

(b/2)^2=(5/2)^2

x^2+5x+25/4=0

(x+5/2)^2=0

x=-5/2

(Hope this helps)

6 0

3 years ago

I like you cookie want go out what me :]

Gelneren [198K]

Answer: lol wut

Step-by-step explanation:

6 0

3 years ago

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