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katrin2010 [14]
3 years ago
11

Please help i don't know

Mathematics
1 answer:
Alex73 [517]3 years ago
5 0
I think its A but in inxtinct it telling me D so i would go with it as the correct answerr






Hope this helps
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What is the cubed root of 64 in exponential form? <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B64%7D%20" id="TexFor
Goshia [24]

Answer:

Step-by-step explanation:

    64^(1/3)       in English it is 64 to the one third power

8 0
3 years ago
According to the diagram below, In which hemisphere is it DAY and WINTER?
Vanyuwa [196]
I think se cuz it still has sunlight but it’s not too close
6 0
3 years ago
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What are the coordinates of the point on the directed line segment from (−1,−8) to (5,−2) that partitions the segment into a rat
Lana71 [14]

Answer:

There are two possible options: P(x,y) = (1, -6) or P(x,y) = (3, -4).

Step-by-step explanation:

There are two possible options depending on what the point of origin is. Vectorially speaking, we can determine the coordinates of the point that partitions the segment is described below:

P(x,y) = A(x,y) + r\cdot [B(x,y) - A(x,y)] (1)

Where:

A(x,y) -  Point of origin.

B(x,y) - Point of destination.

r - Partition factor.

Option 1: A(x,y) = (-1, -8), B(x,y) = (5, -2), r = \frac{1}{3}

P(x,y) = (-1, - 8) + \frac{1}{3}\cdot [(5,-2)-(-1,-8)]

P(x,y) = (-1, -8) + \frac{1}{3}\cdot (6,6)

P(x,y) = (-1,-8) + (2,2)

P(x,y) = (1, -6)

Option 2: A(x,y) = (5,-2), B(x,y) = (-1,-8), r = \frac{1}{3}

P(x,y) = (5,-2) + \frac{1}{3}\cdot [(-1,-8)-(5,-2)]

P(x,y) = (5,-2) +\frac{1}{3}\cdot (-6,-6)

P(x,y) = (5,-2) +(-2,-2)

P(x,y) = (3, -4)

There are two possible options: P(x,y) = (1, -6) or P(x,y) = (3, -4).

4 0
3 years ago
HELP ME IT OVERDOO and i need it badly
IceJOKER [234]

Answer:

The answer to your question should be B.  OC

6 0
3 years ago
Read 2 more answers
Pls help me I’m stuck
erik [133]

Answer:

19.98 ft^2

Step-by-step explanation:

Area of a trapezium formula: \frac{1}{2}h(a+b)

so, 1/2 multiplied by 3.7(4.3+6.5)= 19.98

6 0
3 years ago
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