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2 years ago

14

A function where the independent variable is an exponent. f(x) = ab^x, where a and b are real numbers with a # 0, b>0, and b

# 1
A: exponential growth
B: exponential decay
C: exponential function

1 answer:

Alex787 [66]2 years ago

3 0

Answer:

C

Step-by-step explanation:

C, the answer is exponential function

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In quadrilateral abcd the measures of the angles are represented by measure angle a=6x-2, measure angle b=6x+5, measure angle c=

OleMash [197]

$\bf \textit{sum of all interior angles in a polygon}\\\\ S = 180(n-2)~~ \begin{cases} n=\stackrel{number~of}{sides}\\[-0.5em] \hrulefill\\ n = \stackrel{quadrilateral}{4} \end{cases} \\\\\\ \stackrel{\measuredangle a}{(6x-2)}~~+~~\stackrel{\measuredangle b}{(6x+5)}~~+~~\stackrel{\measuredangle c}{(8x+2)}~~+~~\stackrel{\measuredangle d}{(3x+10)}~~=~~180(4-2)$

$\bf 23x+15=180(2)\implies 23x+15=360\implies 23x=345 \\\\\\ x = \cfrac{345}{23}\implies \boxed{x = 15} \\\\\\ \stackrel{\measuredangle c}{8x+2}\implies 8(15)+2\implies 122$

8 0

2 years ago

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Which function has a range of y<3?<br> y=3(2)<br> y=2(3)<br> O y=-(2)* +3<br> O y= (2)* - 3

VARVARA [1.3K]

option C is correct.

<u>Step-by-step explanation:</u>

If a function is defined as

$f(x)=a^x$ where, a>0, then the range of the function is greater than 0.

$a^x>0$ .... (1)

Option A: Using inequity (1),

$2^x>0$

Multiply both side by 3.

$3(2^x)>0$

The range of first function is y>0. Therefore option A is incorrect.

Option B: Using inequity (1),

$3^x>0$

Multiply both side by 2.

$2(3^x)>0$

The range of second function is y>0. Therefore option B is incorrect.

Option C: Using inequity (1),

$2^x>0$

Multiply both side by -1.

$-2^x$

Add 3 on both the sides.

$-2^x+3$

$y$

The range of first function is y<3. Therefore option C is correct.

Option D: Using inequity (1),

$2^x>0$

Subtract 3 from both the sides.

$2^x-3>-3$

$y>-3$

The range of second function is y>-3. Therefore option D is incorrect.

7 0

3 years ago

Find the value of c so that (x+1) is a factor of the polynomial p(x)

Crank

Answer:

The answer is in the step by step below (image)

Step-by-step explanation:

4 0

2 years ago

How would I reduce this to lowest terms?

Andrew [12]

Since "a" is on the top and the bottom, you can simplify that

$\frac{a^2b^2}{ac}$

$\frac{ab^2}{c}$

6 0

2 years ago

Solve -6f + 13 = 2f - 11

igor_vitrenko [27]

Answer:

f = 3

Step-by-step explanation:

Solve for f:

13 - 6 f = 2 f - 11

Subtract 2 f from both sides:

13 + (-6 f - 2 f) = (2 f - 2 f) - 11

-6 f - 2 f = -8 f:

-8 f + 13 = (2 f - 2 f) - 11

2 f - 2 f = 0:

13 - 8 f = -11

Subtract 13 from both sides:

(13 - 13) - 8 f = -13 - 11

13 - 13 = 0:

-8 f = -13 - 11

-13 - 11 = -24:

-8 f = -24

Divide both sides of -8 f = -24 by -8:

(-8 f)/(-8) = (-24)/(-8)

(-8)/(-8) = 1:

f = (-24)/(-8)

The gcd of -24 and -8 is -8, so (-24)/(-8) = (-8×3)/(-8×1) = (-8)/(-8)×3 = 3:

Answer: f = 3

4 0

3 years ago

Read 2 more answers