Answer:
A) x² + 2x + 6
B) x² + 2x - 7
C) ¼(x²+2x+1))
D) 6x²+12x+6
E) -x²-2x-1
Step-by-step explanation:
A) f(x) + 5 =x²+2x+1 + 5
= x² + 2x + 6
B) f(x)-8,=x^2+2x+1-8
= x² + 2x - 7
C) ¼f(x) = ¼(x²+2x+1)
D) 6f(x) = 6(x²+2x+1) = 6x²+12x+6
E) -f(x) = -(x²+2x+1) = -x²-2x-1
Answer:
Seven
Step-by-step explanation:
Let G7, G8, and G9 be the numbers of students in the respective grades.
Then, G7 + G8 + G9 = LCM of G8 and G9
<em>Data:
</em>
G8 = 5
G9 = 3
<em>Calculations:
</em>
<em>Multiples of 5</em>: 1 2 10 15
<em>Multiples of 3</em>: 1 3 6 9 15
The <em>LCM</em> of 5 and 3 is 15.
G7 + 5 + 3 = 15 Combine like terms
G7 + 8 = 15 Subtract 8 from each side
G7 = 7
There are seven students in Grade 7.
Answer:
d. -38
Step-by-step explanation:
Arithmetic sequence concepts:
The general rule of an arithmetic sequence is as follows:
In which d is the common diference between each term.
We can expand the general equation to find the nth term from the first, by the following equation:
In this question:
17th term:
So the correct answer is:
d. -38
m3 = 110°
Step-by-step explanation:
m1 = 180° - m4 ( sum of angles in a straight angle )
m1 = 180° - 150° = 30°
m3 = 180° - (m2 + m1) ← sum of angles in a triangle
m3 = 180° - (40 + 30 )° = 180° - 70° = 110°
