Find the sum of the first 7 terms of the following series, to the nearest integer.

Mathematics

1 answer:

Virty [35]3 years ago

5 0

Answer:

$r = 2.5 \\ sum = \frac{a( {r}^{n - 1} )}{r - 1} \\ = \frac{125( {2.5}^{7 - 1} )}{7 - 1} \\ = \frac{30517.6}{6} \\ = 5086.3$

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