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Vlad1618 [11]
3 years ago
12

Find the sum of the first 7 terms of the following series, to the nearest integer.

Mathematics
1 answer:
Virty [35]3 years ago
5 0

Answer:

r = 2.5 \\ sum =  \frac{a( {r}^{n - 1} )}{r - 1}  \\  =  \frac{125( {2.5}^{7 - 1} )}{7 - 1}  \\  =  \frac{30517.6}{6}  \\  = 5086.3

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Julli [10]
3 times 4 is equal to 12
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3 years ago
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