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harkovskaia [24]
3 years ago
6

A cab charges $1.45 for the flat fee and $0.55 for each mile. Write and solve an inequality to determine how many miles Ariel ca

n travel if she has $35 to spend.  $1.45 + $0.55x ≥ $35;
 x ≥ 61 miles $1.45 + $0.55x ≤ $35
; x ≤ 61 miles $0.55 + $1.45x ≥ $35;
 x ≥ 23 miles $0.55 + $1.45x ≤ $35; x ≤ 23 miles
Mathematics
2 answers:
sashaice [31]3 years ago
8 0
Hello! So, the $1.45 is a one time fee. The $0.55 is what goes up per each mile driven. C and D are out, because the $1.45 does not multiply per mile. Ariel has $35 to spend and can't spend anymore than that. This problem written out is $1.45 + $0.55x <= 35.The answer is B.
Ivanshal [37]3 years ago
8 0

Answer:

<em>The correct option is:   $1.45 + $0.55x ≤ $35 ;  x ≤ 61 miles</em>

Step-by-step explanation:

Suppose, the number of miles Ariel can travel =x

The cab charges $1.45 for the flat fee and $0.55 for each mile. So, <u>the total charges for x miles</u> =\$1.45+\$0.55x

Given that, she has $35 to spend. That means, <u>the total charges must be less than or equal to $35</u>.

So, the inequality will be:   \$1.45+\$0.55x\leq \$35

Solving the above inequality....

1.45+0.55x\leq 35\\ \\ 0.55x\leq 35-1.45\\ \\ 0.55x\leq 33.55\\ \\ x\leq \frac{33.55}{0.55}\\ \\ x\leq 61

So, the number of miles Ariel can travel is 61 miles.

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\large\underline{\sf{Solution-}}

Given that,

In <u>triangle TPQ, </u>

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As it is given that, <u>RS || PQ</u>

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⇛∠TRS = ∠TPQ [ Corresponding angles ]

⇛ ∠TSR = ∠TPQ [ Corresponding angles ]

\rm\implies \: \triangle TPQ \:  \sim \: \triangle TRS \:  \:  \:  \:  \:  \:  \{AA \}

<u>Now, We know </u>

Area Ratio Theorem,

This theorem states that :- The ratio of the area of two similar triangles is equal to the ratio of the squares of corresponding sides.

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{ar( \triangle \: TRS)}  = \dfrac{ {PQ}^{2} }{ {RS}^{2} }

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = \dfrac{ {6}^{2} }{ {3}^{2} }

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = \dfrac{36 }{9}

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = 4

\rm\implies \:ar( \triangle \: TPQ)  = 60 \:  {cm}^{2}

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