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Mkey [24]
3 years ago
13

James traveled 153 miles in 2 hours. If he continues at a constant speed, how many miles can

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
7 0

Answer:

612

Step-by-step explanation:

take 153 and  2 and divide

153/2=76.5

This answer is your rate in mph, so now take this and multiply by hours given  

76.5*8=612 use a calculator.

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How are mountains and plateaus alike?
IgorLugansk [536]

Answer:

It is similar to a mountain in that it is dramatically higher than what is immediately around it. But mountains usually have a distinct apex or peak that is very small relative to the base and not typically level. Plateaus and mesas have tops only a little smaller than the base, and relatively flat. If the aspect ratio is less than 1, plateau. If greater than 1, mesa.

Step-by-step explanation:

8 0
3 years ago
How do I write 3x+y=7 in slope intercept form
Cloud [144]

slope intercept form

y= mx+b

3x+y =7

subtract 3x from each side

y = -3x+7

3 0
3 years ago
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Yolanda is planning out her square vegetable garden. One side 3 feet. What<br> is the perimeter? *
IRISSAK [1]
The perimeter is 12 feet. This is because a square has equal sides. So if one side of the square garden is 3 feet then the other sides are 3 feet as well. To find the perimeter you add 3 + 3 + 3 + 3 (since there are four sides) and your answer is 12. Hope this helps!
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3 years ago
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What is the slope of the line perpendicular to 2x-3y=8
Elanso [62]

Answer:

X=11/2

Step-by-step explanation:

2x=8+3

2x=11

x=11/2

5 0
2 years ago
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In order to justify this claim for the Ferengi a sample of 16 coils is taken. For this sample set, the mean warp phase flux is f
Kay [80]

Answer:

The responses to these question can be defined as follows:

Step-by-step explanation:

n = 16\\\\  \bar{x}= 73.7\\\\\sigma = 12\\\\a = 0.05\ or\  a = 0.10\\\\H_{o} \ : \mu = 68\\\\H_{a} \ : \mu \neq 68\\\\a = 0.05\\\\

critical values =\pm t0.025,15 = \pm 2.131\\\\

(n-1) = 15^{\circ}\\\\a = 0.10\\\\

critical values= \pm t0.05,15 = \pm 1.753\\\\

(n-1) = 15^{\circ}\\\\

Testing the statistic values:

t = \frac{x-\mu_{0}}{ \frac{s}{\sqrt{n}}}\\\\

  = \frac{73.7-68}{(\frac{12}{\sqrt{16}})}\\\\\  = \frac{5.7}{(\frac{12}{4})}\\\\  = \frac{5.7}{(3)}\\\\  = 1.9\\

Test statistic ta = -1.90\ lies

The critical values\pm t_{0.05,15} =\pm 1.753

It is in the region of dismissal. We dismiss the 10% significant null hypothesis.

t_a = 1.90 \\\\df = 15\\\\a = 0.05\\\\p-value = 076831\\\\

P - value is greater than the level of significance a= 0.05  

Null hypothesis we don't reject. At a 95% level, the claim is justified.

t_a = 1.90\\\\ df = 15\\\\  a = 0.10\\\\p-value = 076831\\\\

P - value below the meaning level a = 0.10, we reject the hypothesis null. At a level of 90% the claim is not justified.

3 0
3 years ago
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