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almond37 [142]
4 years ago
14

Which element has an isotope mass number of 32 and is used as an ecological tracer?

Chemistry
1 answer:
HACTEHA [7]4 years ago
7 0

Phosphorus is the answer because it is used for tracking a plant's uptake of fertiliser from the roots to the leaves. Phosphorus has a mass number of 30, but has several isotopes such as Phosphorus-32, which can be used to trace phosphorylated molecules.

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Why did Thomson’s results from experimenting with cathode rays cause a big change in scientific thought about atoms?
IceJOKER [234]

Answer:

D, because he discovered electrons

Explanation:

8 0
3 years ago
Read 2 more answers
What is the ph of a buffer prepared by adding 0.809 mol of the weak acid ha to 0.608 mol of naa in 2.00 l of solution? The disso
Anarel [89]

The pH of the buffer is 6.1236.

Explanation:

The strength of any acid solution can be obtained by determining their pH. Even the buffer solution strength of the weak acid can be determined using pH. As the dissociation constant is given, we can determine the pKa value as the negative log of dissociation constant value.

pKa=-log[H] = - log [ 5.66 * 10^{-7}]\\ \\pka = 7 - log (5.66)=7-0.753=6.247\\\\pka = 6.247

The pH of the buffer can be known as

pH = pK_{a} + log[\frac{[A-]}{[HA]}}]

The concentration of [A^{-}] = Moles of [A]/Total volume = 0.608/2 = 0.304 M\\

Similarly, the concentration of [HA] = \frac{Moles of HA}{Total volume} = \frac{0.809}{2} = 0.404

Then the pH of the buffer will be

pH = 6.247 + log [ 0.304/0.404]

pH = 6.247 + log 0.304 - log 0.404=6.247-0.517+0.3936=6.1236

So, the pH of the buffer is 6.1236.

5 0
4 years ago
The amount of a chemical solution is measured to be 2 liters.
irinina [24]
2 liters may be 1.5 to 1.9 rounded up to 2 or 2.1 or 2.4 rounded down to 2.

2 - 1.5 = 0.5

percent error = (absolute error / quantity) * 100

percent error = 0.5/2 * 100% = 0.25 * 100% = 25%

Choice C. 25%.
3 0
3 years ago
HELP!!!
vladimir2022 [97]

Answer:

2.5 × 10⁻⁵ M H₃O⁺ and 4.0 × 10⁻¹⁰ M OH⁻.

Explanation:

<em>∵ pH = - log[H₃O⁺]</em>

∴ 4.6 = - log[H₃O⁺].

∴ log[H₃O⁺] = - 4.6.

∴ [H₃O⁺] = 2.51 x 10⁻⁵.

∵ [H₃O⁺][OH⁻] = 10⁻¹⁴.

[H₃O⁺] = 2.51  x 10⁻⁵ M.

∴ [OH⁻] = 10⁻¹⁴/[H₃O⁺] = 10⁻¹⁴/(2.51  x 10⁻⁵ M) = 3.98 × 10⁻¹⁰ M ≅ 4.0 × 10⁻¹⁰ M.

<em>So, the right choice is: 2.5 × 10⁻⁵ M H₃O⁺ and 4.0 × 10⁻¹⁰ M OH⁻.</em>

4 0
4 years ago
Read 2 more answers
Whick ions profuce similar colors in the flame tests?
arlik [135]

Ba2+ and Cu2+, and Sr2+ and Li+

5 0
3 years ago
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