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Ilya [14]
3 years ago
12

After mixing the solutions in a separatory funnel, the stopper should be ________and the liquid should be ________and the layers

allowed to separate. When you get close to the interface between the layers, ________the funnel and________until the first layer______ is collected. _______to collect the second layer.
Chemistry
1 answer:
sdas [7]3 years ago
4 0

Answer:

The answer is below

Explanation:

The separation technique is used for separating immiscible liquids.

When separating, the stopper has to be removed when draining the lower layer so as to prevent a vacuum. If vacuum is allowed, the draining rate will reduce and stop.

The liquid should be mixed by shaking the funnel and then opening the stopcock so as the vent out gases.

When near interface between the layers, you should set your eye level so that you do not drain up to the second layer.

After completely draining the first layer, the second layer should be collected in a new flask.

After mixing the solutions in a separatory funnel, the stopper should be removed and the liquid should be mixed thoroughly and the layers allowed to separate. When you get close to the interface between the layers, get eye level with the funnel and slow the draining until the first layer is collected. Switch to a new flask to collect the second layer.

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The scores obtained by a group of boys in a test are 1,3,0,7,8,3,9,9,9,3
Crazy boy [7]
Mean=5.3
Median=5
Mode=3 and 9
4 0
3 years ago
How many resonance structures are there for [S2CO]2- ?
Irina-Kira [14]

Answer:

Three

Explanation:

1. Draw a Lewis structure

  • Put the least electronegative atom (C) in the centre
  • Attach the O and two S atoms to the C.
  • Add enough electrons to give each atom an octet.

2. Draw the resonance structures

You should get one of the structures below.

It has a double bond and two single bonds.

The resonance structures will have the double bond in each of the other two positions.

5 0
3 years ago
Uranium–232 has a half–life of 68. 9 years. A sample from 206. 7 years ago contains 1. 40 g of uranium–232. How much uranium was
ioda

Half-life can be given as the time required by the substance to reduce to half of its original concentration. The original mass of Uranium was 11.2 grams.

<h3>What is the expression of half-life?</h3>

The half-life for the reaction can be expressed as;

A_t=A_0(\dfrac{1}{2})^\dfrac{t}{t1/2}

Where the final mass of the product is, A_t=1.40\;\rm g

The time for the reduction is given as, t=206.7\;\rm years

The half-life of the compound is given as, t1/2=68.9\;\rm years

The original concentration (A_0) of the Uranium is given as,

\rm 1.40\;g=\textit A_0(\dfrac{1}{2} )^{\dfrac{206.7}{68.9}}\\\\1.40\;g= \textit A_0(\dfrac{1}{2} )^3\\\\\textit A_0=11.2\;\rm grams

The original mass of uranium-232 has been 11.2 grams.

Learn more about half-life, here:
brainly.com/question/24710827

8 0
2 years ago
Bob mixed 5 mg of sodium hydroxide pellets in 100 mL of water. Describe how the rate of the solution changes when he adds 1 mg m
cluponka [151]

Answer:

As Bob add more solute to dissolves, the rate of solution will be decreases

Explanation:

At certain temperature the maximum amount of solute dissolve in the specific amount of solution or solvent.

There are many factors that affect solubility of the solute in solvent. Nature of the solute also affects the rate of solubility.

Temperature also affects the rate of solubility. Solubility increase when the temperature increases.

Pressure: Change in pressure have no effect on the rate of solubility

The rate of solution:  is a measure that how fast a substance dissolves in solvent.

Amount of solute already dissolved affect the rate of solution. If a solvent have little amount of solute in the solution it dissolve quickly. But when you have more solute in the solution the process was slower.

1 g of lead dissolves in 100 g of water at room temperature.  Similarly 5 mg of sodium hydroxide pellet dissolve in 100ml of water at room temperature.

So if Bob add 1 mg more of NaOH in the same 100ml of water the rate of the solubility decreases.

As there are some factors that decrease the solubility rate of NaOH pellet as follow:

• large size of the solute dissolve slowly as the solubility process take on      the surface of the solute particles, powders dissolve fast.

• less amount of solvent with ratio to solute

• saturated solution

So due to all above reasons the rate of the solubility decreases upon adding a little more amount of NaOH pellet.

4 0
3 years ago
Read 2 more answers
What are the 4 factors that affect the dissolving of a gas
lara [203]
Nature of the solute and solvent - The amount of solute that dissolves depends on what type of solute it is.  While only 1 gram of lead (II) chloride can be dissolved in 100 grams of water at room temperature, 200 grams of zinc chloride can be dissolved. This means that a greater amount of zinc chloride can be dissolved in the same amount of water than lead II chloride.
Temperature - Increasing the temperature not only increases the amount of solute that will dissolve but also increases the rate at which the solute will dissolve. For gases, the reverse is true. An increase in temperature decreases both solubility and rate of solution.

Pressure - Changes in pressure have practically no effect on solubility. For gaseous solutes, an increase in pressure increases solubility and a decrease in pressure decreases solubility.  Example:  When the cap on a bottle of soda pop is removed, pressure is released, and the gaseous solute bubbles out of solution. This escape of a gas from solution is called effervescence.

Stirring - Stirring brings fresh portions of the solvent in contact with the solute.  Stirring, therefore, allows the solute to dissolve faster.

Hope this helps!! (If not I'm sorry!)

7 0
3 years ago
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