Answer:
0.425 L
Explanation:
Given the information from the question. We know that the water heat evaporation is given by 2261 KJ/kg. Therefore, for each Kg of vapor, 2261 is required.
To calculate the amount of water evaporated by 960 KJ is as follows
= (1/2260)*960 =0.425 Kg
In other words, 0.425 of water is evaporated by 960 KJ.
To calculate the volume of water, we have mass and density. Therefore, Volume = Mass/Density = 425g/1g/ml = 0.425 L.
Therefore, water evaporated is 0.425 L
Unfortunately, your question is incomplete So, according to the attached picture of the complete question we will explain the answer:
according to the reaction equation:
C(s) + 2H2(g) ↔ CH4(g) ΔH° = -74.6KJ
So the true answer will be
D i and ii
- as by adding more C and it is a reactant so the reaction will go rightward to the product to decrease the C to achieve the equilibrium again, the movement of the reaction towards the products will make the CH4 increase
- and by decreasing the Heat and the heat here is as a product as the reaction is exothermic so by decreasing the heat the reaction will go toward the products to increase the heat and achieve the equilibrium again, and that also makes the CH4 increase as it is a product.
So the true answer is
D i and ii as the attached photo
Answer: The weight of the object on earth =441N
Weight of the object on moon = 72N
The correct answer is pholem tissue
Atomic percentages<u>: 68% of copper and 32% of nickel.</u>
How this is calculated?
The given alloy is 100 g ,
m(Cu) = 0,7 · 100 g = 70 g.
m(Ni) = 0,3 · 100 g = 30 g.
n(Cu) = m(Cu) ÷ M(Cu) = 70 g ÷ 63,546 g/mol
n(Cu) = 1,10 mol.
n(Ni) = m(Ni) ÷ M(Ni) = 30 g ÷ 58,71 g/mol
n(Ni) = 0,51 mol
n(Cu) : n(Ni) = 1,10 mol : 0,51 mol
%(Cu) = 1,1 mol ÷ 1,61 mol = 0,68 = 68 %.
Similarly, %(Ni)=32%
What are Cu-Ni alloys?
- Cu-Ni alloys are alloys of copper (base metal with the largest individual content) and nickel with or without other elements, whereby the zinc content may not be more than 1%.
- When other elements are present, nickel has the largest individual content after copper, compared with each other element.
- As with other copper alloys, it is necessary to distinguish between wrought alloys, which are processed to semi-finished products, and cast alloys, from which castings are produced by various casting processes.
To know more about Cu-Ni alloys, refer:
brainly.com/question/16856761
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