4 years ago

It is necessary to make sure the check register

Mathematics

1 answer:

12345 [234]4 years ago

4 0

Yes very much so .....

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(7-15-3+5-7)×1 step by step

Tresset [83]

Answer:

-13

Step-by-step explanation:

(7−15−3+5−7)⋅1

Subtract 15 from 7 to get −8.

(−8−3+5−7)×1

Subtract 3 from −8 to get −11.

(−11+5−7)×1

Add −11 and 5 to get −6.

(−6−7)×1

Subtract 7 from −6 to get −13.

−13

6 0

3 years ago

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Does anybody know what is −15÷3/5?

Yanka [14]

I hope this helps you

-15÷3
_____

5

-5
___

5

-1

4 0

3 years ago

Write the equation of a circle with center (6,4) that passes through the coordinate (2,1). In your final answer, include all of

kari74 [83]

R^2=(x-6)^2+(y-4)^2

r^2=(6-2)^2+(4-1)^2, r^2=16+9=25

(x-6)^2+(y-4)^2=25

8 0

3 years ago

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A piano has 52 white keys. Write and use an equation to find the number of octaves on a piano keyboard.

Firdavs [7]

There are 7 keys in each octave (C,D,E,F,G,A and B) so it would make sense to divide 52 to 7.
52/7=7 octaves and 3 extra kets

3 0

3 years ago

Find the equation of a parabola with a vertical axis and its vertex at the origin and passing through the point (-2, 3)

vredina [299]

a vertical axis, I assume it means a vertical axis of symmetry, thus it'd be a vertical parabola, like the one in the picture below.

$\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} y=a(x- h)^2+ k\qquad \qquad \leftarrow vertical\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{}{ h},\stackrel{}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=0\\ k=0 \end{cases}\implies y=a(x-0)^2+0 \\\\\\ \textit{we also know that } \begin{cases} x=-2\\ y=3 \end{cases}\implies 3=a(-2-0)^2+0\implies 3=4a \\\\\\ \cfrac{3}{4}=a~\hspace{10em}y=\cfrac{3}{4}(x-0)^2+0\implies \boxed{y=\cfrac{3}{4}x^2}$

8 0

3 years ago