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2 years ago

HELP!!!! I can’t figure this out

Mathematics

1 answer:

grin007 [14]2 years ago

5 0

Answer:

$A.\,\orange{ \bold{ \frac{x - 3}{3x + 1} }}$

Step-by-step explanation:

$\frac{x + 2}{ {x}^{2} + 5x + 6 } \div \frac{3x + 1}{ {x}^{2} - 9} \\ \\ = \frac{x + 2}{ {x}^{2} + 3x + 2x+ 6 } \div \frac{3x + 1}{ {x}^{2} - {(3)}^{2} } \\ \\ = \frac{\cancel{x + 2}}{ \cancel{{({x}+ 3)}} \cancel{(x+ 2) }} \times \frac{\cancel{( {x} + 3)}( {x} - {3)}}{3x + 1} \\ \\ = \purple{ \bold{ \frac{x - 3}{3x + 1} }}$

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ExplainHow to find the product 3/8 x 7/9

iris [78.8K]

Answer:

7/8

Step-by-step explanation:

well first when you put them together like 3/8 and 7/9 you have to simplfy first. You have to cross simplify 3 and 3. Since they are the saem both turn into one. Now you mulitpy. 7 times 1 is 7 and 8 times one is 8. 7/8

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3 years ago

Read 2 more answers

Question 1- explain how Sheldon immediately knew howard was incorrect?

Dmitrij [34]

Answer:

Part 1) In the procedure

Part 2) In the procedure

Step-by-step explanation:

Part 1) Observing the graph

The roots are x=-1/2 and x=4

Remember that, the roots are the x-values when the value of y is equal to zero (the x-intercepts)

That's why Sheldon immediately realizes Howard's solution is incorrect

Part 2) we have

$y=2x^{2}-7x-4$

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

equate the equation to zero

$2x^{2}-7x-4=0$

$a=2\\b=-7\\c=-4$

substitute

$x=\frac{-(-7)(+/-)\sqrt{-7^{2}-4(2)(-4)}} {2(2)}$

$x=\frac{7(+/-)\sqrt{49+32}} {4}$

Howard's error is in this step, is wrong with the sign of the number 7, is positive instead of negative

$x=\frac{7(+/-)\sqrt{81}}{4}$

$x=\frac{7(+/-)9}{4}$

$x=\frac{7(+)9}{4}=4$

$x=\frac{7(-)9}{4}=-1/2$

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