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SSSSS [86.1K]
4 years ago
14

Multiply (x−3)(x+2)

Mathematics
2 answers:
Phantasy [73]4 years ago
4 0

We FOIL, multiply firsts, outers, inners and lasts, and add them all up.

(x-3)(x+2) = x·x + 2x - 3x + (-3)(2) = x² - x - 6

Answer: x² - x - 6

LenKa [72]4 years ago
3 0

Answer:

<u><em>x^2 - x - 6</em></u>

Step-by-step explanation:

(x - 3) (x + 2)

  1. you can use the distributive property and multiply
  2. first, you multiply the first x by the second x.
  3. that would be x^2.
  4. then, you multiply the first x by 2.
  5. which is 2x. by now you should have x^2 + 2x.
  6. now, you multiply -3 by the second x.
  7. this equals -3x.
  8. now, you have x^2 + 2x - 3x.
  9. next, you multiply -3 by +2.
  10. this would result in -6.
  11. now combine all of the solutions you got and you should have:
  12. x^2 + 2x - 3x - 6
  13. the last step is to combine like terms.
  14. x^2 is an only term, so leave that alone.
  15. +2x and -3x are like terms. so, you want to add these.
  16. that would remain as x^2 - x
  17. now, -6 is an only term as well. so, just leave that in the end.
  18. in conclusion, your answer is x^2 - x - 6
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A (0, 2) and B (6,6) are points on the straight line ABCD.
elena-14-01-66 [18.8K]

Answer:

(18, 14)

Step-by-step explanation:

We know that C and D lie on the line AB and BC = CD = AB. Then we need to use the distance formula and equation of the line AB to find the other two coordinates.

The distance formula states that the distance between two points (x_1,y_1) and (x_2,y_2), the distance is denoted by: \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}. Let's find the distance between A and B:

d = \sqrt{(6-0)^2+(6-2)^2}=\sqrt{6^2+4^2} =\sqrt{36+16} =\sqrt{52} =2\sqrt{13}

Now say the coordinates of D are (a, b). Then the distance between D and B will be twice of 2√13, which is 4√13:

4√13 = \sqrt{(6-a)^2+(6-b)^2}

Square both sides:

208 = (6 - a)² + (6 - b)²

Let's also find the equation of the line AB. The y-intercept we know is 2, so in y = mx + b, b = 2. The slope is (6 - 2) / (6 - 0) = 4/6 = 2/3. So the equation of the line is: y = (2/3)x + 2. Since (a, b) lines on this line, we can put in a for x and b for y: b = (2/3)a + 2. Substitute this expression in for b in the previous equation:

208 = (6 - a)² + (6 - b)²

208 = (6 - a)² + (6 - (2/3a + 2))² = (6 - a)² + (-2/3a + 4)²

208 = a² - 12a + 36 + 4/9a² - 16/3a + 16 = 13/9a² - 52/3a + 52

0 = 13/9a² - 52/3a - 156

13a² - 156a - 1404 = 0

a² - 12a - 108 = 0

(a + 6)(a - 18) = 0

a = -6 or a = 18

We know a can't be negative so a = 18. Plug this back in to find b:

b = 2/3a + 2 = (2/3) * 18 + 2 = 12 + 2 = 14

So point D has coordinates (18, 14).

8 0
4 years ago
Read 2 more answers
Write the equation of a line that passes through the point (-7, 3) and is
kondor19780726 [428]

Answer:

y-axis is 0 (-7,4)   i guess

Step-by-step explanation:

8 0
3 years ago
Solve using Substitution<br> y = -1x - 5<br> 4x - 8y = 4
Liula [17]

Answers:

Step-by-step explanations:

4 0
4 years ago
What is the value of |-7| - |3|
Rudik [331]

Answer:

4 is the correct answer

Step-by-step explanation:

|-7| = 7

|3| = 3

7 - 3 = 4

3 0
3 years ago
U-3/4=4 please help me ty
Ne4ueva [31]
To solve the equation:

\frac{u - 3}{4}  = 4 \\ \frac{u - 3}{4}  \times 4 = 4  \times 4\\ u - 3 = 4 \times 4 \\ u - 3 + 3 = 16 + 3 \\ u = 16 + 3 \\ u = 19

Therefore, the answer is u=19.

Hope it helps!
8 0
4 years ago
Read 2 more answers
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