Answer:
H(11)=101
Step-by-step explanation:
The function we have is:
and we need to find the value of
this is evaluating the function 
when the value of t is 
So, first we substitute in H(t):
we solve the expression:
the answer is that when , the function has the value 
It would be (9,5) or (9 9)
Answer:
38
38 38 38 38 38 38 38 38okay so all you're going to do 4 * 3 + 4 * 4 what is going to give you 12 +16
-8,-6,-4
-10,-6,0
these are the possible test points for your three intervals
