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dybincka [34]
3 years ago
11

Please help me

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
3 0

Answer:

C. y-7=2(x-6)

Step-by-step explanation:

y2-y1/x2-x1

7-(-9)/6-(-2)

7+9/6+2

16/8

m=2

y-y1=m(x-x1)

y-7=2(x-6)

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Answer:

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Step-by-step explanation:

Our expression is: \frac{1}{3} \sqrt[3]{81}.

Let's focus on the cube root of 81 first. What's the prime factorisation of 81? It's simply: 3 * 3 * 3 * 3, or 3^3*3. Put this in for 81:

\sqrt[3]{81} =\sqrt[3]{3^3*3}=\sqrt[3]{3^3} *\sqrt[3]{3}

We know that the cube root of 3 cubed will cancel out to become 3, but the cube root of 3 cannot be further simplified, so we keep that. Our outcome is then:

\sqrt[3]{3^3} *\sqrt[3]{3}=3\sqrt[3]{3}

Now, let's multiply this by 1/3, as shown in the original problem:

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Thus, the answer is \sqrt[3]{3}.

<em>~ an aesthetics lover</em>

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