Absolutely anything! It all depends on what the equation is. Variables can be any number with exception of 0 As a denominator. Otherwise pick anything as long as the end results come out to the number you are seeking.

5 0

3 years ago

How do you solve 3^(4x) = 3^(5-x)?

trasher [3.6K]

3^(4x) = 3^(5 - x)
4x = 5 - x
4x + x = 5
5x = 5
x = 5/5 = 1
x = 1

3 0

3 years ago

What is the product?<br> (3a^2b^4) (-8ab^3)

sladkih [1.3K]

Answer:

-24a^3b^7

Step-by-step explanation:

(3a^2b^4)(-8ab^3) Original equation

-24a^3b^7 You have to multiply the coefficients, but because of

the power rule, you have to add the exponents with each other.

Hope this helps!

8 0

3 years ago

Read 2 more answers

Find the LCM of this set of numbers. 5 and 25

Andrej [43]

Answer:

Step-by-step explanation:

LCM = Least Common Multiple

To find the LCM, start by listing multiples, or the product of any two numbers.

5: 5, 10, 15, 20, 25, 30, 35...

25: 25, 50, 75, 100, 125, 150, 175...

Now, let's find the LCM by selecting the smallest shared multiple out of the lists we made.

5: 5, 10, 15, 20, 25, 30, 35...

25: 25, 50, 75, 100, 125, 150, 175...

Therefore, 25 is the LCM of 5 and 25.

4 0

3 years ago