Answer:
Ben spent 9 dollars
Step-by-step explanation:
Answer:
lineHO parallel lineEN - Given
lineHW = lineNW - Given
angle HWO <u>congruent</u> angle EWN Vertical Angles
angle OHW <u>congruent</u> angle ENW Alternate interior angles
Thus triangle HOW congruent triangle NEW
[wouldn't let me use symbols sorry]
It’s 16 because Ik I did it before so do y worry
Answer:
5 units
Step-by-step explanation:
According to the given statement Δ XYZ is translated 4 units up and 3 units left to yield ΔX'Y'Z' which means that each point in ΔXYZ is moved 4 units up and moved 3 units left.
To find the distance of each corresponding point we will use the Pythagorean theorem which states that the square of the length of the Pythagorean of a right triangle is equal to the sum of the squares of the length of other legs
The square of the required distance = 4^2+3^2 = 16+9 =25
By taking root of 25 we get:
√25 = 5
Thus, we can conclude that the the distance between any two corresponding points on ΔXYZ and ΔX′Y′Z′ is 5 units.
..
Answer:
OPTION A: 2x + 3y = 5
Step-by-step explanation:
The product of slopes of two perpendicular lines is -1.
We rewrite the given equation as follows:
2y = 3x + 2
⇒ y = 
The general equation of the line is: y = mx + c, where 'm' is the slope of the line.
Here, m = 
.
Therefore, the slope of the line perpendicular to the line given = 
because 
.
To determine the equation of the line passing through the given point and a slope we use the Slope - One - point formula which is:
y - y₁ = m(x - x₁)
The point is: (x₁, y₁) = (-2, 3)
Therefore, the equation is:
y - 3 = (x + 2) $
⇒ 3y - 9 = -2(x + 2)
⇒ 3y - 9 = -2x - 4
⇒ 2x + 3y = 5 is the required equation.
