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3 years ago

5 thousands 2 tens 4 ones +4 thousands 3 hundreds 2 ones

Mathematics

2 answers:

Nostrana [21]3 years ago

5 0

5,024+4,302=9,326, or 9 thousands 3 hundreds 2 tens 6 ones.

anastassius [24]3 years ago

4 0

That would be 5,024 + 4,302= 9,326, or 9 thousands, 3 hundreds, 2 tens, and 6 ones

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A rectangle is shown. All angles are right angles. The length of one side is 2 x and the length of another side is 3 x + 3. The

Doss [256]

Answer:

Step-by-step explanation:

Alright, lets get started.

Please refer the diagram I have attached.

The perimeter of the rectangle will be : $2\times(\ length+width)$

The perimeter will be : $2 \times(2x+3x+3)$

The perimeter will be : $10x+6$

As per given question, the perimeter is given as 146 unit.

So,

$10x+6=146$

Subtracting 6 on both sides

$10x=140$

$x=14$

Plugging the value x in sides, the sides will be $2 \times 14=28$ and

$3 \times 14+3=45$

Hence the length of the longer side is 45 units. : Answer

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3 years ago

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What is the alt code for the division sign? 50 points

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Answer:

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Step-by-step explanation:

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3 years ago

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strojnjashka [21]

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3 years ago

2x+4x+6x=10x+84 please help solve

Natasha2012 [34]

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dedylja [7]

1. 5 in and 1/3 in: Area = 5/3 in^2

2. 5 in and 4/3 in: Area= 20/3 in^2

3. 5/2 in and 4/3 in: Area=10/3 in^2

4. 7/6 in and 6/7 in: Area = 1 in^2

Step-by-step explanation:

1. 5 in and 1/3 in

Here,

$Let\\l=5\\w=\frac{1}{3}\\Area=l*w\\=5*\frac{1}{3}\\=\frac{5}{3}\ in^2$

2. 5 in and 4/3 in

Here,

$l= 5\ in\\w=\frac{4}{3}\ in\\Area=l*w\\=5*\frac{4}{3}\\=\frac{20}{3}\ in^2$

3. 5/2 in and 4/3 in

$let\\l=\frac{5}{2}\\w=\frac{4}{3}\\Area= \frac{5}{2}*\frac{4}{3}\\=\frac{20}{6}=\frac{10}{3}\ in^2$

4. 7/6 in and 6/7 in

Let

$l=\frac{6}{7}\\w=\frac{7}{6}\\Area=l*w\\=\frac{6}{7}*\frac{7}{6}\\=1\ in^2$

Hence,

1. 5 in and 1/3 in: Area = 5/3 in^2

2. 5 in and 4/3 in: Area= 20/3 in^2

3. 5/2 in and 4/3 in: Area=10/3 in^2

4. 7/6 in and 6/7 in: Area = 1 in^2

Keywords: Rectangle, Area

Learn more about rectangles at:

#LearnwithBrainly

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