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Neko [114]
4 years ago
10

Which statement best describes f(x)= -2 √x-7 +1 –6 is in the domain of f(x) but not in the range of f(x). –6 is not in the domai

n of f(x) but is in the range of f(x). –6 is in the domain of f(x) and in the range of f(x). –6 is neither in the domain of f(x) nor in the range of f(x).
Mathematics
1 answer:
Archy [21]4 years ago
5 0

Answer:

B. -6 does not belong to the domain but belongs to the range of f(x).

Step-by-step explanation:

We have the function, f(x)=-2\sqrt{x-7}+1.

So, the domain of the function is obtained when x-7\geq 0 i.e. x\geq 7

That is, the domain is {x | x≥ 7}.

Now as we have,

x\geq 7 → x-7\geq 0 → \sqrt{x-7} \geq 0 → -2\sqrt{x-7} \leq 0 → -2\sqrt{x-7}+1 \leq 1.

That is, f(x)\leq 1

Thus, the range of the function f(x) is {y | y≤ 1}.

Thus, we can see that,

-6 does not belong to the domain but belongs to the range of f(x).

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The data of players of volleyball tournament, the mean is 56.5, median is 53, range is 56 and interquartile range is 20

<h3>What is mean, median and mode of a data set?</h3>

The mean of the data is the average value of the given data. The mean of the data is the ratio of the sum of all the values of data to the total number of values of data.

The median of the data is the middle value of the data set when it arrange in ascending or descending order.

Mode of a data set is the value, which occurs most times for that data set. The value which has the highest frequency in the given set of data is known as the mode of that data set.

The stem-and-leaf plot shows the number of digs for the top 15 players at a volleyball tournament. The table is attached below.

The data according to the table is,

41,41,43,43,45,50,52,53,54,62,63,63,67,75,97

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\mu=\dfrac{41+41+43+43+45+50+52+53+54+62+63+63+67+75+97}{15}\\\mu=\dfrac{849}{15}\\\mu=56.5

  • The median is.

The arranged data according to the table is,

41,41,43,43,45,50,52,53,54,62,63,63,67,75,97

Here, the middle value is 53. Thus, the median is 53.

  • The modes from least to greatest are , , and.

Mode is the data which occur most offen. Here the order of modes from least to greatest is,

41   41   43   43   45   50   52   53   54   62   63   63   67   75   97  

  • The range is.

Lowest value in data is 41 and highest is 97. Thus, the range is,

r=97-41\\r=56

  • The interquartile range is.

The third quartile of data is 63 while first quartile is 43. Thus, the interquartile range is.

IQR=63-23\\IQR=20

Thus, the data of players of volleyball tournament, the mean is 56.5, median is 53, range is 56 and interquartile range is 20.

Learn more about the mean, median and mode here;

brainly.com/question/14532771

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