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2 years ago

Please help me!!!!!!!

Mathematics

1 answer:

AlekseyPX2 years ago

5 0

Your answer is 11.32 because each segment is 1 point behind the three or the hundredths place.

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The perimeter of a rectangular garden is 108 meters. The length is 6 meters longer than twice the width, find the dimensions of

Natalka [10]

Answer:

width=16

length=38

Step-by-step explanation:

perimeter of a rectangle=2(length+width)

108/2=length+ width

54=length+ width

54-width=length

also:

length-6= 2×width

length=2width +6

now you can put the length we found, in the second equation:

54-width=2width+6

54-6=2width+width

48=3width

width=16

now do the exact same thing with one of the equations we created in the beginning.

either this:

54-width=length

or this:

length=2width +6

as the 1st one is simpler, I use that:

54-(16)=length

length=38

8 0

2 years ago

The diameter of a Frisbee is 12 in. What is the area of the Frisbee?

Alina [70]

we know that

Area of the circle is equal to

$A=\pi r^{2}$

where

r is the radius

in this problem

$diameter=12\ in \\ radius=diameter/2\\ radius=12/2\\ radius=6\ in$

$A=3.14* 6^{2}$

$A=113.04 in^{2}$

therefore

the answer is the option

d. 113.04 sq. in.

8 0

2 years ago

Read 2 more answers

1. Determine the zeros of f(x) = x3 – 3x2 – 16x + 48? Somebody explain it please?:/

inn [45]

$x^{2} - 3x^{2} - 16x + 48 = 0$

$x^{2} (x - 3) - 16(x - 3) = 0$

$(x - 3) ( x^{2} - 16) = 0$

$(x - 3) (x - 4) (x + 4) = 0$

$x = -4, 3, 4$

The zeros are: -4, 3, 4

6 0

2 years ago

Verify which of the following are identities.

-Dominant- [34]

Answer:

Only the second equation is an identity

Step-by-step explanation:

$8 \frac{\tan^2(\theta)}{\sec(\theta)} \csc^2(\theta)=8 \csc(\theta)$

$\tan^2(\theta)\csc^2(\theta)=\sec^2(\theta)$

<u>You can confirm it: </u>

$\frac{\sin^2(\theta)}{\cos^2(\theta)}\cdot \frac{1}{\sin^2(\theta)}= \frac{1}{cos^2(\theta)}= \sec^2(\theta)$

<u>Therefore</u>

$8 \frac{\sec^2(\theta)}{\sec(\theta)} =8 \csc(\theta)$

$8 \frac{\sec(\theta)}{1} =8 \csc(\theta)$

$8\sec(\theta)=8\csc(\theta)$

<h2>It is not an Identity</h2>

<u>Let's the second one</u>

$13 \frac{\tan^2(\theta)}{\sec(\theta)} \csc^2(\theta)=13\sec(\theta)$

In this case, we already performed the calculations, so it is true. It is an Identity.

3 0

2 years ago

Equality of fractions

Svetach [21]

Answer:

Fractions are equal when one fraction can be obtained from the other.

Step-by-step explanation:

equality means a relationship between two quantities or, more generally two mathematical expressions, asserting that the quantities have the same value, or that the expressions represent the same mathematical object.

6 0

1 year ago