Answer:
The correct answer is -
Genotypes: 1 heterozygous dominant: 1 recessive
Phenotypes: 1 long hair cat: 1 short hair cat
probability: 50% chances of both long and short hair cats
Explanation:
It is given that long hair is a dominant represented by H, over the short hair represented by h. In the cross of a heterozygous cat for long hair with a cat with short hair, would produce H, h and h, h gametes respectively.
Cross: Hh × hh
H h
h Hh hh
h Hh hh
In this Punnett, there are two heterozygous long hair offspring produced and two short-hair cats.
So, Genotypes: 1 heterozygous dominant: 1 recessive
Phenotypes: 1 long hair cat: 1 short hair cat
probability: 50% chances of both long and short hair cats
Answer:
Increase aldosterone and decrease ADH
Explanation:
Aldosterone causes reabsorption of sodium ions while Antidiuretic hormone (ADH) causes reabsorption of water. Aldosterone also causes water reabsorption due to increased osmotic pressure by reabsorbing sodium ions. But for water reabsorption, Aldosterone has to work along with ADH to increase permeability for water. If we increase Aldosterone and decrease ADH, the sodium ions will be reabsorbed while water cannot be reabsorbed due to decreased permeability of DCT and collecting tubules for water.
Answer:
In eukaryotes, it is well known that polyadenylation is required to produce the mature messenger RNA (mRNA) molecule and it provides stability to the mRNA during translation initiation. In prokaryotic organisms, polyadenylation is required for the degradation of the mRNA in a mechanism that involves three steps: endonucleolytic cleavage, polyadenylation and exonucleolytic degradation. Moreover, it is also important to note that no evidence of polyadenylation has bee reported in some prokaryotes including the halophilic bacteria Haloferax volcanic (Slomovic et al. 2005).
Citation:
Slomovic, S., Laufer, D., Geiger, D., & Schuster, G. (2005). Polyadenylation and degradation of human mitochondrial RNA: the prokaryotic past leaves its mark. Molecular and cellular biology, 25(15), 6427-6435.
