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Zielflug [23.3K]
3 years ago
5

Akash has already spent 4 minutes on the phone, and he expects to spend 1 more minute with every phone call he routes. In all,ho

w many phone calls does Akash have to route to spend a total of 37 minutes on the phone?
Mathematics
2 answers:
wariber [46]3 years ago
6 0
I am almost positive 6 phone calls 
Leya [2.2K]3 years ago
4 0
37 or u38 not completely sure
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How do you solve this?
puteri [66]

Answer:

Width: 7

Length: 14

Step-by-step explanation:

The area of a rectangle can be found my multiplying the length by the width. We do not know neither the length nor the width. However, we do know that the length is 7 feet longer than the width. Because we do not know the value of either side, let's let x represent the width.

Since the length is 7 feet longer, we can represent the length by x+7.

Now that we have our values for the length and the width we can multiply them together to find our area.

(x)(x+7)=x^{2} +7x

Now we have our equation, so we can address the changes made by the original question. The original question states that when 7 is added to both the length and width the area becomes 3 times larger. To do so simply increase each side by 7 by adding 7 to the original values.

(x+7)(x+14)

And multiply our area by 3.

3(x^{2} +7x)

set these equal to each other to find your new equation.

(x+7)(x+14)=3(x^{2} +7x)

Now you need to solve for x. To do this first muliply (x+7) and (x+14).

(x+7)(x+14)=\\x^{2} +14x+7x+98=\\x^{2} +21x+98

Then multiply 3(x^{2} +7x)

3(x^{2} +7x)=\\3x^{2} +21x

Now you can begin solving for x.

x^{2} +21x+98=3x^{2} +21x

Subtract x^{2} from both sides.

21x+98=2x^{2} +21x

Subtract 21x from both sides.

98=2x^{2}

Divide by 2.

49=x^{2}

And finally take the sqaure root of both sides.

\sqrt{x^{2} }=\sqrt{49}\\x=7

Remember, because we are dealing with length, there cannot be negative. So while normally we would get both +7 <em>and</em> -7, in this case we <em>only </em>get +7.

Now that we have the value of x, we can plug it into our original values.

For width we simply get 7.

For length we get 7+7=14

To check our answer we cna multiply 7 by 14 to get 98. Then we can add 7 to our length and width to get 14 and 21. Multiply these together and we get 294. 294 divided by 3 is 98, proving our answer correct.

7 0
3 years ago
Robin can run 1.71 kilometers in 10 minutes. How far can she run in 1.5 hours?
Flura [38]

Answer:

I think is 15.39 kilometers

Step-by-step explanation:

1 hour=60 minutes +.5 hours =90 minutes = 9 x 1.71 = 15.39

7 0
2 years ago
There exist infinitely many common fractions $\frac{a}{b}$ , where $a &gt; 0$ and $b &gt; 0$ and for which $\frac{3}{5} &lt; \fr
vredina [299]

Answer:

3/5 has the smallest denominator

Step-by-step explanation:

Question:

There exist infinitely many common fractions a/b , where a > 0 and b > 0 and for which 3/5 < a/b< 2/3. Of these common fractions, which has the smallest denominator? Express your answer as a common fraction.

Solution

A Common fraction is a rational number written in the form: a/b. Where a and b are both integers.

The denominator and numerator in this case are greater than zero. That is, they are non zeros.

The least common denominator (LCD) of two non- zero denominators is the smallest whole number that is divisible by each of the denominators.

To find the smallest denominator between 3/5 and 2/3, we would convert the fractions to equivalent fractions with a common denominator by finding their LCM (lowest common multiple).

When comparing two fractions with like denominators, the larger fraction is the one with the greater numerator and the smaller fraction is one with the smaller numerator.

In our solution after comparing, the smaller fraction would have the smallest denominator.

Find attached the solution.

3 0
3 years ago
Write the phase "3 times the difference of 5 and y equals 4" as a variable expression:
worty [1.4K]

Answer:

3(5-7)=4

Step-by-step explanation:

6 0
3 years ago
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Divide 124 in the ratio of 3:1 plsssss
UNO [17]
The answer is 93 to 31 :)
6 0
3 years ago
Read 2 more answers
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