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3 years ago

14

Same as other one, Whoever solve first with best explanation gets brainlest and also 21 points!

2 answers:

ozzi3 years ago

8 0

Answer:

Equation C is correct. :)

OverLord2011 [107]3 years ago

4 0

Answer:

I got answer A and B

Step-by-step explanation:

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Four years after opening an account that paid simple interest of 4.25% annually, a depositor withdrew the $2,380 in interest ear

satela [25.4K]

Answer:

Step-by-step explanation:

In order to figure out how much money was left in the account after the interest was withdrawn, we have to first find out how much money was initially deposited to earn that amount of interest! The means to find that initial investment is found in the simple interest formula

prt = I, where

p is the initial investement,

r is the interest rate in decimal form,

t is the time in years, and

I is the interest earned. Notice that we have all those things but the p.

Filling in:

p(.0425)(4) = 2380 and

.17p = 2380 so

p = 14000

That means that 14000 was initially invested. If the depositor withdrew the 2380, then

14000 - 2380 is the amount left in the account, namely, $11620

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3 years ago

A loss of 500 in stock market is worse than a gain of $200

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700 stock market is worse than gain

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Can someone pls help me?<br> Determine the measures of the unknown angles in the<br> figure below.

IceJOKER [234]

Answer:

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Step-by-step explanation:

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3 years ago

Write a number with the digit<br> 8 in the tens place

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3 years ago

Read 2 more answers

The length of a 200 square foot rectangular vegetable garden is 4feet less than twice the width. Find the length and width of th

inna [77]

Answer:

Length = 18.099 ft

Width = 11.049 ft

Step-by-step explanation:

let the length of the field be x ft

and the width be y ft

as per the condition given in problem

x=2y-4 -----------(A)

Also the area is given as 200 sqft

Hence

xy=200

Hence from A we get

y(2y-4)=200

taking 2 as GCF out

2y(y-2)=200

Dividing both sides by 2 we get

$y(y-2)=100$

$y^2-2y=100$

subtracting 100 from both sides

$y^2-2y-100=0$

Now we solve the above equation with the help of Quadratic formula which is given in the image attached with this for any equation in form

$ax^2+bx+c=0$

Here in our case

a=1

b=-1

c=-100

Putting those values in the formula and solving them for y

$y=\frac{-(-2)+\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

$y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

Solving first

$y=\frac{2+\sqrt{4+400}{2}$

$y=\frac{2+\sqrt{404}{2}$

$y=\frac{2+20.099}{2}$

$y=\frac{22.099}{2}$

$y=11.049$

Solving second one

$y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

$y=\frac{2-\sqrt{4+400}{2}$

$y=\frac{2-\sqrt{404}{2}$

$y=\frac{2-20.099}{2}$

$y=\frac{-18.99}{2}$

$y=-9.045$

Which is wrong as the width can not be in negative

Our width of the field is

y=11.099

Hence the length will be

x=2y-4

x=2(11.049)-4

x=22.099-4

x=18.099

Hence our length x and width y :

Length = 18.099 ft

Width = 11.049 ft

4 0

3 years ago