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otez555 [7]
3 years ago
14

A circle with the center at the origin and a radius length of 7

Mathematics
1 answer:
Novay_Z [31]3 years ago
6 0

(7,0), (-7,0), (0,7), (0,-7)

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This is algebra 1 math problem <br>f (×)=2/5x+10
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f^−1(x)=−25+5x/2
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Solve the following proportion by cross multiplying:<br> x / 8 = 28 / 32
AveGali [126]
Since it is an equality that means the left side of the equation (x/8) has to be equal to the right side of the equation (28/32). One way you can solve for x is to isolate it. Since it’s an equality like we said you have to do to the left side the same that you would do to the right side to isolate x. So if I multiply by 8 on the left I need to also multiply by 8 on the right. So 8* (x/8) becomes just x since 8x/8 becomes 8/8 * x which is 1 *x. On the right side we do 8 *(28/32) which becomes 28 * 8/32 which becomes 7. So x = 7.
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2 years ago
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allochka39001 [22]

Answer:

Step-by-step explanation:

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6 0
3 years ago
5+7k&gt;=-30 and -4k +4&gt;20​
Slav-nsk [51]

Answer:

\large\boxed{-5\leq k

Step-by-step explanation:

5+7k\geq-30\ \wedge\ -4k+4>20\\\\5+7k\geq-30\qquad\text{subtract 5 from both sides}\\7k\geq-35\qquad\text{divide both sides by 7}\\\boxed{k\geq-5}\\\\-4k+4>20\qquad\text{subtract 4 from both sides}\\-4k>16\qquad\text{change the signs}\\4k

7 0
3 years ago
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