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3 years ago

A circle with the center at the origin and a radius length of 7

Mathematics

1 answer:

Novay_Z [31]3 years ago

6 0

(7,0), (-7,0), (0,7), (0,-7)

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Answer to the question

viktelen [127]

Answer:

x = 48.

Step-by-step explanation:

If AE is 921, then EC is equivalent to that. First, you subtract 9 from 921, then divide by nineteen to get your answer: x = 48.

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3 years ago

Marie wrote this expression to describe the number of cherries she would give each friend.

Maksim231197 [3]

The correct answer is A Marie does not know how many cherries she has to share. She knows she is sharing her cherries equally with 3 friends

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3 years ago

Please answer this question below.

Katarina [22]

In a theatre room, there are 4 rows of chairs. There are 4 columns of chairs. How many chairs are there in the theatre room?

4x4=16

There are 16 chairs in the theatre room.

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3 years ago

Read 2 more answers

A pillar is 15 m high the diameter is 84 cm what is the surface area

NARA [144]

Answer:

1416 cm

Step-by-step explanation:

Use calcutor shows everthinh

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2 years ago

Find the equation, (f(x) = a(x - h)2 + k), for a parabola containing point (2, -1) and having (4, -3) as a vertex. What is the s

Nataliya [291]

Answer:

$f(x)=\frac{1}{2}x^2-4x+5$

Step-by-step explanation:

A parabola is written in the form

$f(x)=a((x-h)^2+k)$ (1)

where:

$h$ is the x-coordinate of the vertex of the parabola

$ak$ is the y-coordinate of the vertex of the parabola

$a$ is a scale factor

For the parabola in the problem, we know that the vertex has coordinates (4,-3), so we have:

$h=4$ (2)

$ak=-3$

From this last equation, we get that $a=\frac{-3}{k}$ (3)

Substituting (2) and (3) into (1) we get the new expression:

$f(x)=-\frac{3}{k}((x-4)^2+k) = -\frac{3}{k}(x-4)^2 -3$ (4)

We also know that the parabola contains the point (2,-1), so we can substitute

x = 2

f(x) = -1

Into eq.(4) and find the value of k:

$-1=-\frac{3}{k}(2-4)^2-3\\-1=-\frac{3}{k}\cdot 4 -3\\2=-\frac{12}{k}\\k=-\frac{12}{2}=-6$

So we also get:

$a=-\frac{3}{k}=-\frac{3}{-6}=\frac{1}{2}$

So the equation of the parabola is:

$f(x)=\frac{1}{2}((x-4)^2 -6)$ (5)

Now we want to rewrite it in the standard form, i.e. in the form

$f(x)=ax^2+bx+c$

To do that, we simply rewrite (5) expliciting the various terms, we find:

$f(x)=\frac{1}{2}((x^2-8x+16)-6)=\frac{1}{2}(x^2-8x+10)=\frac{1}{2}x^2-4x+5$

6 0

3 years ago