The Factorization of 121b⁴ − 49 is (11b^2 + 7)(11b^2 - 7).
The equation 121b⁴ − 49
To find the Factorization of 121b⁴ − 49.
<h3>
What is the factor of a^2-b^2?</h3>
The factor of a^2-b^2 is (a+b)(a-b)
We have write the given equation in the form of a^2-b^2
Therefore the factor of the 121b^4 − 49 is (11b^2 + 7)(11b^2 - 7).
To learn more about the factor visit:
brainly.com/question/25829061
Answer:
it moves graph left
Step-by-step explanation:
h=left and right
k=up and down
Answer:
2/10
Step-by-step explanation:
2 of the letters are vowel:
E and I
the fraction in the image is 2 1/2
let's try each choice
1) 2/3 x 5/2 = 10/6 = 5/3
2) 5/4 x 5/2 = 25/8
3) 3/3 x 2 1/2 = 2 1/2
4) 4/5 x 5/2 = 20/10 = 2
who is giving you these questions?
The problem said : -10,8 =-2 and -15,9=-6
