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OLga [1]
3 years ago
15

Which of the following demonstrates the Commutative Property of addition?

Mathematics
1 answer:
Crazy boy [7]3 years ago
5 0

Answer:

To my calculations, I think its the first one, 4+2=2+4

I hope this helps! ^^

Apologizes if you get it wrong-

Step-by-step explanation:

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In the following formula what does x(down)1 equal in terms of other variables.
icang [17]

Answer:

It’s b

Step-by-step explanation:

7 0
2 years ago
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Which point is a solution to y ≤ 3x- 4?<br> O A. (0,4)<br> O B. (-2, 0)<br> OC. (0, 0)<br> OD. (3,1)
Nina [5.8K]

Answer:

<em>(D). (3, 1) </em>

Step-by-step explanation:

y ≤ 3x - 4

<u><em>(A). (0, 4)</em></u>

4 ≤ 3(0) - 4

4 ≤ - 4 <u><em>(False statement)</em></u>

<u><em>(B). (-2, 0)</em></u>

0 ≤ 3(- 2) - 4

0 ≤ - 10 <u><em>(False statement) </em></u>

<u><em>(C). (0, 0)</em></u>

0 ≤ 3(0) - 4

0 ≤ - 4 <u><em>(False statement)</em></u>

<u><em>(D). (3, 1)</em></u>

1 ≤ 3(3) - 4

1 ≤ 5 <u><em>(True statement) </em></u>

4 0
3 years ago
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Please help will give brainliest<br> And happy Halloween
kramer
Answer to the problem is s=0.6
3 0
3 years ago
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What are the coordinates of the fourth point that could be connected with (–8, 0), (1, 0), and (1, –5) to form a rectangle?
sergey [27]
(-8, -5)

To form a rectangle, all the lines must be perpendicular and parallel. If you draw out the points on a coordinate plane then you can find the answer pretty easily. 

Also, this one is easy because all the lines are vertical or horizontal, and when that is the case then you can just see which number in the set hasn't appeared twice (1 appeared twice as an <em>x</em> value, 0 appeared twice as a <em>y </em>value, but -8 has only appeared once as an <em>x</em> and -5 has only appeared once as a <em>y </em>value)
6 0
3 years ago
Help me with this please !!
avanturin [10]

Answer:

see explanation

Step-by-step explanation:

Under a reflection in the line y = - x

a point (x, y ) → (- y, - x ), thus

T(- 1, 3 ) → T'(- 3, 1 )

U(- 1, 10 ) → U'(- 10, 1 )

V(- 2, 4 ) → V'(- 4, 2 )

6 0
3 years ago
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