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3 years ago

5

What two different expressions can be simplified to 3m-8?

1 answer:

ss7ja [257]3 years ago

6 0

There are many ways a problem can be simplified. You can divide by the GCF (Greatest Common Factor) or even factor which depending on where you are in math you may or may not have learned. For your problem, I will use the first method.

3m-8 can be multiplied by any term (keep it simple):

2(3m-8) = 6m-16
4(3m-8) = 12m-32

Your answers should be 6m-16 and 12m-32.

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4 years ago

Read 2 more answers

During a radio contest, $50 is added to the prize money each time a caller answers the contest question incorrectly. The first

Gnoma [55]

Answer:

The expression is $a_{10}$ = 100+(10 - 1)50 .

Step-by-step explanation:

Given as :

The amount of money added as prize money = $50

The amount that first caller will win = $a_{1}$ = $100

Let The amount that 10th caller win = $A

∴ common difference for the callers amount = $50

Now, According to question

<u>The given statement is in arithmetic expression</u>

So, For A.P , The nth term is written as

nth term = first term + (n - 1) × common difference

I.e $a_{10}$ = $a_{1}$ + (n - 1) × common difference

Here n = 10

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3 years ago

El recorrido de una etapa de una vuelta ciclística tiene una longitud de 213 kilometros y un ciclista recorre 2/3 del trayecto e

Maurinko [17]

the question in English

The route of a stage of a cycle tour is 213 km long and a cyclist covers 2/3 of the route in five hours.

a) How many kilometers are left to finish the stage?

b) If he continues with the same average speed, how much time does he have left to finish the stage?

Step 1

we know that

1) Total kilometers of a stage is $213\ km$

2) The cyclist covers $\frac{2}{3}$ of the route

so

the kilometers remaining to finish the stage is equal to

$(1-\frac{2}{3})*213= \frac{1}{3}*213\\ \\=71\ km$

therefore

<u>the answer Part a) is </u>

$71\ km$

Step 2

<u>Find the average speed of the cyclist</u>

we know that

the speed is equal to

$speed=\frac{distance}{time}$

we have

$time=5\ hours\\ distance=\frac{2}{3}*213=142\ km$

substitute

$speed=\frac{142}{5}=28.4\frac{km}{h}$

Step 3

<u>Find the time remaining to finish the stage</u>

we know that

$speed=\frac{distance}{time}$

Solve for the time

$time=\frac{distance}{speed}$

we have

$distance=71\ km\\ speed=28.4\frac{km}{h}$

substitute

$time=\frac{71}{28.4}=2.5\ hours$

therefore

<u>the answer Part b) is</u>

$2.5\ hours$

8 0

3 years ago