Question

During a radio contest, $50 is added to the prize money each time a caller answers the contest question incorrectly. The first

Answer 1

Answer:

The expression is  $a_{10}$ = 100+(10 - 1)50 .

Step-by-step explanation:

Given as :

The amount of money added as prize money =  $50

The amount that first caller will win =  $a_{1}$ = $100

Let The amount that 10th caller win = $A

∴ common difference for the callers amount = $50

Now, According to question

The given statement is in arithmetic expression

So, For A.P , The nth term is written as

nth term = first term  + (n - 1) × common difference

I.e $a_{10}$ = $a_{1}$ +  (n - 1) × common difference

Here n = 10

Or, A = $100 +  (10 - 1) × 50

So, The expression =  $a_{10}$ = 100+(10 - 1)50

Hence, The expression is  $a_{10}$ = 100+(10 - 1)50 . Answer