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JulsSmile [24]
3 years ago
10

On a vacation trip to Canada you realize that the speed limit signs are in km/hour. Unfortunately, your speedometer only reads i

n mph. How fast are you allowed to go if the speed sign says 120 km/hr (rounded to the nearest tenth) ?
Mathematics
2 answers:
Mrac [35]3 years ago
4 0

Answer: 74.6 miles per hour

Step-by-step explanation:

I mile per hour equals 1.609 kilometers per hour. The formula to solve the speed limit is to divide 120 by 1.609.

120/1.609 = 74.6 miles per hour

Annette [7]3 years ago
3 0

Answer:

120 km is 74.56 miles so just round that

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4 0
3 years ago
What is the value of the expression below if y=5
Neko [114]

Answer:

25

Step-by-step explanation:

8*5=40

40+6=46

46-10=36

36-9=25

5 0
3 years ago
Sketch the region that is common to the graphs of x ≥ 2,
Oliga [24]

a. Find the graph of their common region in the attachment

b. The area of the common region of the graphs is 8 units²

<h3>a. How to sketch the region common to the graphs?</h3>

Since we have x ≥ 2, y ≥ 0, and x + y ≤ 6, we plot each graph separately and find their region of intersection.

  • The graph of x ≥ 2 is the region right of the line x = 2.
  • The graph of y ≥ 0 is the region above the line y = 0 or x-axis.
  • To plot the graph of x + y ≤ 6, we first plot the graph of x + y = 6 ⇒ y = -x + 6. Then the graph of x + y ≤ 6 is the graph of y ≤ - x + 6.

So, the graph of x + y ≤ 6 is the region below the line y = - x + 6

From the graph, the regions intersect at (2, 0), (2, 4) and (6, 0)

Find the graph of their common region in the attachment

<h3>b. The area of the common region</h3>

From the graph, we see that the common region is a right angled triangle with

  • height = 4 units and
  • base = 4 units

So, its area = 1/2 × height × base

= 1/2 × 4 units × 4 units

= 1/2 × 16 units²

= 8 units²

So, the area of the common region of the graphs is 8 units²

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6 0
2 years ago
Solve the quadratic equation: 2(x-3)^2-24-0
Keith_Richards [23]

Answer:

x=3+2×sqrt(3)

x=3-2×sqrt(3)

Step-by-step explanation:

2(x-3)²-24=0

2(x-3)²=24

(x-3)²=12

Case 1:

x-3=sqrt(12)=2×sqrt(3)

x=3+2×sqrt(3)

Case 2:

x-3=-sqrt(12)=-2×sqrt(3)

x=3-2×sqrt(3)

7 0
3 years ago
An arithmetic sequence has a first term of 6.3 and a second term of 8.8 Which term has a value of 78.8?
slega [8]
First term [ a ] = 6.3

Common difference [ d ] = 8.8 - 6.3 = 2.5 

Using general term formula,

t_{n} = a + (n-1)d

78.8 = 6.3 + (n-1)*2.5

2.5*(n-1) = 72.5 [ Dividing both sides by 2.5 ]

n-1 = 29

n = 30

Hence, 78.8 is the 30th term in the arithmetic series.
4 0
3 years ago
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