Answer:
No. pp you can fit in a van: 6,
No. pp you can fit in a bus: 20
Step-by-step explanation:
Let v = # of pp in vans, and let b = # of pp in buses:
8v + 9b = 228,
4v + 5b = 124
If we solve this system of equations by substitution, we isolate the first eq. for v and then substitute into the bottom eq:
v = 228-9b/8,
Substitute v = 228-9b/8 into bottom eq:
[4 * 228-9b/8 + 5b = 125]
[228+b/2=124]
[228+b = 248]
[b = 20]
Now substitute 20 to find no. of pp in the vans:
v = 228 - 9(20)/8 = 228 - 180/8 = 48/8 = 6
11 is the answer
hope this helps
Answer:
<h2>x = -8 or x = 2</h2>
Step-by-step explanation:
![(a+b)^2=a^2+2ab+b^2\qquad(*)\\\\-------------------------------\\\\x^2+6x-16=0\qquad\text{add 16 to both sides}\\\\x^2+6x=16\\\\x^2+2(x)(3)=16\qquad\text{add}\ 3^2\ \text{to both sides}\\\\\underbrace{x^2+2(x)(3)+3^2}_{(*)}=16+3^2\\\\(x+3)^2=16+9\\\\(x+3)^2=25\Rightarrow x+3=\pm\sqrt{25}\\\\x+3=-5\ \vee\ x+3=5\qquad\text{subtract 3 from both sides}\\\\\boxed{x=-8\ \vee\ x=2}](https://tex.z-dn.net/?f=%28a%2Bb%29%5E2%3Da%5E2%2B2ab%2Bb%5E2%5Cqquad%28%2A%29%5C%5C%5C%5C-------------------------------%5C%5C%5C%5Cx%5E2%2B6x-16%3D0%5Cqquad%5Ctext%7Badd%2016%20to%20both%20sides%7D%5C%5C%5C%5Cx%5E2%2B6x%3D16%5C%5C%5C%5Cx%5E2%2B2%28x%29%283%29%3D16%5Cqquad%5Ctext%7Badd%7D%5C%203%5E2%5C%20%5Ctext%7Bto%20both%20sides%7D%5C%5C%5C%5C%5Cunderbrace%7Bx%5E2%2B2%28x%29%283%29%2B3%5E2%7D_%7B%28%2A%29%7D%3D16%2B3%5E2%5C%5C%5C%5C%28x%2B3%29%5E2%3D16%2B9%5C%5C%5C%5C%28x%2B3%29%5E2%3D25%5CRightarrow%20x%2B3%3D%5Cpm%5Csqrt%7B25%7D%5C%5C%5C%5Cx%2B3%3D-5%5C%20%5Cvee%5C%20x%2B3%3D5%5Cqquad%5Ctext%7Bsubtract%203%20from%20both%20sides%7D%5C%5C%5C%5C%5Cboxed%7Bx%3D-8%5C%20%5Cvee%5C%20x%3D2%7D)
Answer:
3160
Step-by-step explanation:
3.16 x 10^3
10^3 = 1000
so you move the decimal point three times to the right
I hope this helps