No it is not. If you had two fixed diagonals which are attached in the center, when they move it creates different parallelograms. The area would be close to zero if they were parallel.
Answer:
24 i think
Step-by-step explanation:
I evaluated using he given value
Answer:
B) 3.2 mi
Step-by-step explanation:
1. The midpoints: midpoint formula = <em>((x₁ + x₂)/2, (y₁+ y₂)/2)</em>
upper = ((6 + -4)/2, (8 + 0)/2) --><em> (1, 4)</em>
lower = ((-8 + 2)/2, (3 + -5)/2) --><em> (-3, -1)</em>
2. Distance: distance formula = <em>√((x₁ - x₂)² + (y₁ - y₂)²)</em>
√((1 + 3)² + (4 + 1)²) = √(16 + 25) = √41 ≈ 6.403... ≈ <em>6.4</em>
3. Scale: 6.4 * 0.5 mi = 3.2 mi
What is #, is it 1, 2, 3??
Answer:
A
Step-by-step explanation:
