F(x) = x²-4x-5, quadratic function,
Domain (the values if x) is all real numbers.
To find range we should draw a graph or to write an equation in vertex form.
f(x) = x²-4x+4-4-5
f(x) = (x-2)²-9
Point (-2,-9) is the vertex of the parabola, and it is a minimum because a parabola has positive sign in front of x², so it is looking up. Minimum value of y =-9
Range(the values of y) is [-9, ∞)
Checking the <span>discontinuity at point -4
from the left f(-4) = 4
from the right f(-4) = (-4+2)² = (-2)² = 4
∴ The function is continues at -4
</span>
<span>Checking the <span>discontinuity at point -2
from the left f(-2) = </span></span><span><span>(-2+2)² = 0
</span>from the right f(-2) = -(1/2)*(-2)+1 = 2
∴ The function is jump discontinues at -2
</span>
<span>Checking the <span>discontinuity at point 4
from the left f(4) = </span></span><span><span>-(1/2)*4+1 = -1
</span>from the right f(4) = -1
but there no equality in the equation so,
</span><span>∴ The function is discontinues at 4
The correct choice is the second
point </span>discontinuity at x = 4 and jump <span>discontinuity at x = -2</span>
Answer:
54%
Step-by-step explanation:
total animals=27+23=50
