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emmainna [20.7K]
3 years ago
13

What is the length of BC ?

Mathematics
1 answer:
MrRa [10]3 years ago
6 0
Looking at this triangle, we can see that is a form of a 45, 45, 90 triangle
This would mean that 2x-24=x-2
Solve: 2x-24=x-2
subtract x from both sides and add 24 to both sides...
x=22
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Does any one knows the scale factor?
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Hey jm correct answer
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3 years ago
Example 2
Arada [10]

Answer:

y=x-2

Step-by-step explanation:

If you have drawn the graph of y = x^2 - 3x + 1.

To determine the equation of the line which  should be drawn to solve the equation:  x² - 4x +3=0

Simply carry out the subtraction: x^2 - 3x + 1 -(x^2 - 4x +3)

\implies x^2 -3x + 1-x^2 + 4x -3 \\= x^2 - x^2+ 4x - 3x-3  + 1\\=x-2

The equation of the line which should be drawn is: y=x-2

What this means is simply:

If

y = x^2 - 3x + 1$ and $y=x-2,$ then:\\x^2 - 3x + 1=x-2\\x^2 - 3x + 1-x+2=0\\x^2 - 4x + 3=0

5 0
3 years ago
A boy is 3 years more than twice as old as his sister. His sister is 6 years old. How old is the boy?
AlexFokin [52]
The boy is 15 because twice the age of his sister is 12, then you add the three years to it and get 15
3 0
3 years ago
Read 2 more answers
Lily measures the circumference of three pillars.
Mariulka [41]

Answer:

Step-by-step explanation:

7 0
2 years ago
What is the length of the given segments EF and GH?
erastovalidia [21]

Answer:

EF = 5

GH = 5

Step-by-step explanation:

Length of EFis the distance between E(-4, -3) and F (-1, 1).

EF = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

E(-4, -3) = (x_1, y_1)

F(-1, 1) = (x_2, y_2)

EF = \sqrt{(-1 -(-4))^2 + (1 -(-3))^2}

EF = \sqrt{(3)^2 + (4)^2}

EF = \sqrt{9 + 16} = \sqrt{25}

EF = 5

Distance between G(-2, -3) and H(3, -3)

GH = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

G(-2, -3) = (x_1, y_1)

H(3, -3) = (x_2, y_2)

GH = \sqrt{(3 -(-2))^2 + (-3 -(-3))^2}

GH = \sqrt{(5)^2 + (0)^2}

GH = \sqrt{25 + 0} = \sqrt{25}

GH = 5

4 0
3 years ago
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