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emmainna [20.7K]

3 years ago

13

What is the length of BC ?

1 answer:

MrRa [10]3 years ago

6 0

Looking at this triangle, we can see that is a form of a 45, 45, 90 triangle
This would mean that 2x-24=x-2
Solve: 2x-24=x-2
subtract x from both sides and add 24 to both sides...
x=22

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Does any one knows the scale factor?

Black_prince [1.1K]

Yes in science it’s the scale factor of the division barns end. Dive o Ebro dodo ooo
Hey jm correct answer

6 0

3 years ago

Arada [10]

Answer:

y=x-2

Step-by-step explanation:

If you have drawn the graph of $y = x^2 - 3x + 1$ .

To determine the equation of the line which should be drawn to solve the equation: x² - 4x +3=0

Simply carry out the subtraction: $x^2 - 3x + 1 -(x^2 - 4x +3)$

$\implies x^2 -3x + 1-x^2 + 4x -3 \\= x^2 - x^2+ 4x - 3x-3 + 1\\=x-2$

The equation of the line which should be drawn is: y=x-2

What this means is simply:

If

$y = x^2 - 3x + 1$ and $y=x-2,$ then:\\x^2 - 3x + 1=x-2\\x^2 - 3x + 1-x+2=0\\x^2 - 4x + 3=0$

5 0

3 years ago

A boy is 3 years more than twice as old as his sister. His sister is 6 years old. How old is the boy?

AlexFokin [52]

The boy is 15 because twice the age of his sister is 12, then you add the three years to it and get 15

3 0

3 years ago

Read 2 more answers

Lily measures the circumference of three pillars.

Mariulka [41]

Answer:

Step-by-step explanation:

7 0

2 years ago

What is the length of the given segments EF and GH?

erastovalidia [21]

Answer:

$EF = 5$

$GH = 5$

Step-by-step explanation:

Length of EFis the distance between E(-4, -3) and F (-1, 1).

$EF = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$E(-4, -3) = (x_1, y_1)$

$F(-1, 1) = (x_2, y_2)$

$EF = \sqrt{(-1 -(-4))^2 + (1 -(-3))^2}$

$EF = \sqrt{(3)^2 + (4)^2}$

$EF = \sqrt{9 + 16} = \sqrt{25}$

$EF = 5$

Distance between G(-2, -3) and H(3, -3)

$GH = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$G(-2, -3) = (x_1, y_1)$

$H(3, -3) = (x_2, y_2)$

$GH = \sqrt{(3 -(-2))^2 + (-3 -(-3))^2}$

$GH = \sqrt{(5)^2 + (0)^2}$

$GH = \sqrt{25 + 0} = \sqrt{25}$

$GH = 5$

4 0

3 years ago