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kumpel [21]
3 years ago
13

What is the simplified form of x+3/x^2-x-12 times x-4/x^2-8x+16?

Mathematics
1 answer:
Alenkinab [10]3 years ago
3 0
<span> \frac{x+3}{x^2-x-12} * \frac{x-4}{x^2-8x+16} \\= \frac{x+3}{(x-4)(x+3)}* \frac{x-4}{(x-4)(x-4)}  = \frac{1}{x-4}* \frac{1}{x-4} = \frac{1}{(x-4)^2}    *  </span><span>x-4/x^2-8x+16


Hope that helps
</span><span />
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Answer:

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The length of the triangle are as follows x - 4 , x + 6 and 2x - 18 . The hypotenuse should be 2x - 18 . The hypotenuse is the longest side of a right angle triangle.

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