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Ray Of Light [21]
3 years ago
5

Find the area of the regular polygon.Round to the nearest tenth.16 ft​

Mathematics
1 answer:
Sladkaya [172]3 years ago
8 0

<u>Given</u>:

Given that the side of the regular polygon is 16 feet.

We need to determine the area of the polygon.

<u>Area of the polygon:</u>

The area of the polygon can be determined using the formula,

Area =\frac{s^2 n}{4 \ tan \frac{180}{n}}

where n is the number of sides,

s is the side length.

Substituting n = 3 and s = 16, we get;

Area =\frac{16^2 (3)}{4 \ tan \frac{180}{3}}

Simplifying, we get;

Area =\frac{(256) (3)}{4 \ tan \ 60}

Area = \frac{768}{6.928}

Dividing, we get;

Area = 110.85

Rounding off to the nearest tenth, we have;

Area = 110.9

Thus, the area of the regular polygon is 110.9 square units.

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Sophia cuts two pieces of ribbon for a craft project. The first ribbon is 7.74 cm long. The second ribbon is 9.281 cm long. What
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Plz help, 15 points!
Eduardwww [97]

Answer:

2x+3y=-6

Step-by-step explanation:

Let the line is y=mx+b where m is slope and b is y-intercept.

The line is parallel to 2x+3y=3, slope of both the lines will be same.

Find the slope of 2x+3y=3

3y=3-2x\\y=-\frac{2}{3}x+1

Slope of line=-\frac{2}{3}

m=-\frac{2}{3}

So the line will be y=-\frac{2}{3}x+b

It passes through (3,-4).

-4=-\frac{2}{3}\times 3+b\\-4=-2+b\\b=-2\\

Hence the line is y=-\frac{2}{3}x-2

y=-\frac{2}{3}x-2\\3y=-2x-6\ \ \ \ \ \ \ (Multiply both sides by 3)\\2x+3y=-6

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