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Alekssandra [29.7K]
3 years ago
12

Sophia cuts two pieces of ribbon for a craft project. The first ribbon is 7.74 cm long. The second ribbon is 9.281 cm long. What

is the total length of the two ribbons if she lines them up end to end? Enter your answer in the box.
Mathematics
2 answers:
docker41 [41]3 years ago
6 0
Hello! So Sophia cuts two pieces of ribbon that are different lengths and lines them up together. To find the total length of the two ribbons, let's add them up. Because there is no digit in the thousandths place, we'll fill that in with a zero. Now, let's add up the numbers. 9.281 + 7.740 = 17.021. There. The total length of the ribbons is 17.021 cm long.
Nady [450]3 years ago
4 0

Answer:

the answer is 17.021

Step-by-step explanation:

i did the test the answer was correct. to help with simple algebra go to mathpapa a algebra math calculator

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The 59th and 4th team of an Ap are - 61 and 64 respectively. Show that the common differences is - 2.5 and 23rd term is 16.5​
Mnenie [13.5K]

Answer:

See answers below

Step-by-step explanation:

T59 = a+58d = -61

T4 = a+3d = 64.

Subtract

58d-3d = -61-64

-55d = -125

d =125/55

d = 25/11

Get a;

From 2

a+3d = 64

a+3(25/11) = 64

a = 64-75/11

a = 704-75/11

a = 629/11

T23 = a+22d

T23 = 629/11+22(25/11)

T23 = 1179/11

3 0
3 years ago
There are 10 true-false questions and 20 multiple choice questions from which to choose a five-question quiz how many ways can t
beks73 [17]

Answer:

In 68229 ways can the quiz be selected such that there is atleast three multiple choice questions

Step-by-step explanation:

Given:

Number of True or false questions= 10

Number of multiple choice questions= 20

To Find:

How many ways can 5 questions can be selected if there must be at least three multiple choice questions =?

Solution:

Combination

A combination is a mathematical technique that determines the number of possible arrangements in a collection of items where the order of the selection does not matter. In combinations, you can select the items in any order.  

The question States there sholud be ATLEAST 3 multiple choice question,

So, we may have

(3 Multiple choice question and 2 true or false question) or

(4 Multiple choice question and 1 true or false question) or

(5 Multiple choice question and 0 true or false question)

Required Number of ways = (20C3 X10C2) +(20C4 X10C1) + (20C5 X10C0)

Required Number of ways =(\frac{20!}{20!(20-3)!}\times\frac{10!}{10!(10-2)!})+(\frac{20!}{20!(20-4)!} \times \frac{10!}{10!(10-1)!}) +(\frac{20!}{20!(20-4)!} \times \frac{10!}{10!(10-0)!})

Required Number of ways = ( 1140 x 42) + (4845 x 10) +(15504 x 1)

Required Number of ways = 47880+48450+15504

Required Number of ways = 68229

3 0
3 years ago
If you drive your car for 4.5 hours at an average speed at 70 miles per hour how far did you go ?
vodka [1.7K]
I think it would be 315. because 4.5*70..but im not sure
3 0
3 years ago
What is the slope of the line that passes through (8,4) and (6,7)?
bija089 [108]
slope=\frac{y_2-y_1}{x_2-x_1}\\\\ 
(x_1,y_1)=(8,4)\\ 
(x_2,y_2)=(6,7)\\\\
 slope=\frac{7-4}{6-8}=\frac{3}{-2}=-\frac{3}{2}\\\\
Slope\ is\ equal\ to\ -\frac{3}{2}.

4 0
3 years ago
Out of a group of 120 students that were surveyed about winter sports 28 said they ski 53 said they snowboard Sixteen of the stu
hjlf

Answer:

P ( snowboard I ski)​ = 0.5714

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Ski

Event B: Snowboard.

28 out of 120 students ski:

This means that P(A) = \frac{28}{120} = 0.2333

16 out of 120 do both:

This means that P(A \cap B) = \frac{16}{120} = 0.1333

P ( snowboard I ski)​

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.1333}{0.2333} = 0.5714

So

P ( snowboard I ski)​ = 0.5714

7 0
3 years ago
Read 2 more answers
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