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3 years ago

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A total of 258 tickets were sold for the school play. They were either adult tickets or student tickets. The number of student t

ickets sold was two times the number of adult tickets sold. How many adult tickets were sold?

1 answer:

blondinia [14]3 years ago

5 0

There are 86 adult tickets were sold

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The p-value for a two-sided test of the null hypothesis H0: μ = 10 is 0.06.(a) Would a 95% confidence interval for μ include the

emmasim [6.3K]

Answer:

a) Yes b) No

Step-by-step explanation:

Given that the p value for a two-sided test of the null hypothesis H0: μ = 10

is 0.06

a) $p value = 0.06.\\Confidence level = 95%\\Significance level = 100-95 = 5%\\Alpha = 0.05\\\\p \geq \alpha is true$

Hence we accept null hypothesis

This implies that 10 will be within the confidence interval of 95%

b) If confidence level = 90%

$\alpha = 0.10\\p value = 0.06\\p \leq 0.10$

So we have to reject null hypothesis.

So we do not have 10 in the confidence interval

The reason is the lower the confidence level, the narrower the confidence interval. In this case, 10 has gone outside the narrower interval hence we get this.

7 0

3 years ago

An 8- pound bag of apples costs $17.50.What is the unit price?

hammer [34]

To find the answer to this we will set up a proportion. Lets do it:-

$\frac{8}{17.50} = \frac{1}{x}$

Now we will cross multiply:-

7.50 · 1 = 17.50

Next we will divide:-

17.50 ÷ 8 = x

x = 2.18

So, $2.18 per pound of apples.

Hope I helped ya!!

3 0

3 years ago

Read 2 more answers

AP Calculus redo! I know the answer but can't figure out exactly how to get there. Thank you! I want to work through the steps.

Monica [59]

You're approximating

$\displaystyle\int_1^5 x^2\,\mathrm dx$

with a Riemann sum, which comes in the form

$\displaystyle\int_a^b f(x)\,\mathrm dx=\lim_{n\to\infty}\sum_{i=1}^nf(x_i)\Delta x_i$

where $x_i$ are sample points chosen according to some decided-upon rule, and $\Delta x_i$ is the distance between adjacent sample points in the interval.

The simplest way of approximating the definite integral is by partitioning the interval into equally-spaced subintervals, in which case $\Delta x=\dfrac{b-a}n$ , and since $[a,b]=[1,5]$ , we have

$\Delta x=\dfrac{5-1}n=\dfrac4n$

Using the right-endpoint method, we approximate the area under $f(x)$ with rectangles whose heights are determined by their right endpoints. These endpoints are chosen by successively adding the subinterval length to the starting point of the interval of integration.

So if we had $n=4$ subintervals, we'd split up the interval of integration as

$[1,5]=[1,2]\cup[2,3]\cup[3,4]\cup[4,5]$

Note that the right endpoints follow a precise pattern of

$2=1+\dfrac44$
$3=1+\dfrac84$
$4=1+\dfrac{12}4$
$5=1+\dfrac{16}4$

The height of each rectangle is then given by the values above getting squared (since $f(x)=x^2$ ). So continuing with the example of $n=4$ , the Riemann sum would be

$\displaystyle\sum_{i=1}^4\left(1+\dfrac{4i}4\right)^2\dfrac44$

For $n=5$ ,

$\displaystyle\sum_{i=1}^5\left(1+\dfrac{4i}5\right)^2\dfrac45$

and so on, so that the definite integral is given exactly by the infinite sum

$\displaystyle\lim_{n\to\infty}\sum_{i=1}^n\left(1+\dfrac{4i}n\right)^2\dfrac4n$

4 0

3 years ago

Can somebody help me as soon as possible.

Evgen [1.6K]

Answer: x= -0.2

Step-by-step explanation:

4 0

2 years ago

Select ALL sets that are functions:

nataly862011 [7]

2nd and 4th are functions

an x value in a set of functions can only have one y value. however, a y value can have infinite amount of x values

in the 1st and 3rd set, the x value of -2 has 2 y values

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3 years ago