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3 years ago

Bulan rows on a crew team. Her team rows their boat at a split (rate) of

Mathematics

2 answers:

stellarik [79]3 years ago

7 0

500 miles in 2 minutes means you divide 500 by 2 to find what half of 500 is since you do half of 1,

so the answer is

250 m/ min

DENIUS [597]3 years ago

7 0

Answer: 1 min/250 m

Step-by-step explanation:

Given : Bulan rows on a crew team. Her team rows their boat at a split (rate) of 500 m/2 min

To find : Bulan's team's rowing rate in min/m.

For that we need to find the reciprocal of the split rate.

i.e. $\text{Rowing rate}=\dfrac{1}{\text{split rate}}$

i.e. $\text{Rowing rate}=\dfrac{1}{\dfrac{500}{2}}$

i.e. $\text{Rowing rate}=\dfrac{2}{\text{500}}=\dfrac{1}{250}$

i.e. Bulan's team's rowing rate = 1 min/250 m

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rosijanka [135]

Answer:

The balcony seat costs $9, the orchestra seat costs $9 + $6 = $15.

Step-by-step explanation:

Let x is the cost/price of one balcony seat, in dollars.

Then the cost of one orchestra seat is (x+6) dollars, according to the condtion.

The total cost of tickets is

250x + 400*(x+6) = 8250.

Simplify it step by step.

250x + 400x + 2400 = 8250,

650x = 8250 - 2400 = 5850 ====> x = 5850/650 = 9.

Answer. The balcony seat costs $9, the orchestra seat costs $9 + $6 = $15.

Check. 9*250 + 15*400 = 8250. Correct.

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3 years ago

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Ksju [112]

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3 years ago

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If Alex and Mpho have to share R20 in the ratio 2:3,how much will Mpho get?

CaHeK987 [17]

Answer:

Step-by-step explanation:

sum of ratio=2+3=5

Mpho gets=3/5×20=12

4 0

3 years ago

Listed below are the lead concentrations in mu ??g/g measured in different traditional medicines. Use a 0.10 0.10 significance l

laiz [17]

Answer:

We conclude that the mean lead concentration for all such medicines is less than 17 mu.

Step-by-step explanation:

We are given below are the lead concentrations in mu;

6.5 18.5 21.5 5.5 8.5 4.5 4.5 17.5 15.5 20

We have to test the claim that the mean lead concentration for all such medicines is less than 17 mu.

Let $\mu$ = mean lead concentration for all such medicines.

So, Null Hypothesis, $H_0$ : $\mu$ = 17 mu {means that mean lead concentration for all such medicines is equal to 17 mu}

Alternate Hypothesis, $H_A$ : $\mu$ < 17 mu {means that the mean lead concentration for all such medicines is less than 17 mu}

The test statistics that would be used here One-sample t test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n}}}$ ~ $t_n_-_1$

where, $\bar X$ = sample mean lead concentration = $\frac{\sum X}{n}$ = 12.25 mu

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 6.96 mu

n = sample size = 10

So, test statistics = $\frac{12.25 -17}{\frac{6.96}{\sqrt{10}}}$ ~ $t_9$

= -2.16

The value of t test statistics is -2.16.

Now, the P-value of the test statistics is given by the following formula;

P-value = P( $t_9$ < -2.16) = 0.031

Now, at 0.10 significance level the t table gives critical value of -1.383 for left-tailed test. Since our test statistics is less than the critical value of t as -2.16 < -1.383, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean lead concentration for all such medicines is less than 17 mu.

7 0

3 years ago

A white tailed deer can sprint up to 30 miles per hour. American bison can run at speeds up to 3,520 feet per minute. Which anim

mario62 [17]

Answer:

The American bison is 10 miles per hour faster. It can run at 40 miles per hour.

Step-by-step explanation:

See the picture for the conversion. I used unit multiplies to change feet to miles and seconds to minutes.

4 0

1 year ago